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How many permutations of 5 letter can be made without any letters being repeated?
There are 7893600 permutations.
How many different 4 letter combinations can you make with 6 different letters?
6P4 = 6!/(6-4)! = 6 * 5 * 4 * 3 = 360 four letter permutations from 6 different letters.6C4 = 6!/[4!∙(6-4)!] = 15 four letter combinationsfrom 6 different letters.
How many ways can the letters abcdef be arranged?
The number of permutations of the letter ABCDEF is 6 factorial, or 720.
How many permutations are possible of the word yard?
Imagine you have four empty buckets in which to put any of the four letters Y, A, R, D into. At first you have four letters that can be placed in any of the four empty buckets. Once you've placed a letter in a bucket you only have three letters and three empty buckets to choose from. And so on... So there are 4x3x2x1 = 24 permutations of the word YARD.
How many permutations are possible of the word great?
the word great has 5 different letters.. so at 1st place 5 different letters can exist, at 2nd, left 4 letters can exist, at 3rd.. 3 left letters, at 4th, 2 left letters and 5th ..1 left letter.. so for permutation... we do possible options at 1st place X possible options at 2nd place ... and so on till X possible options at 5th place. = 5 X 4 X 3 X 2 X 1 =20 X 6 = 120 so the word great has 120 possible permutations.
How many different three letter permutations can be formed from the letters in the word clipboard?
There are three that I can see, there's clip, board and lip.
How may different nine-letter permutations can be formed from the nine letters in the word isosceles?
9*8*7 / 2! / 3!
How many different five letter permutations can be formed fron the letters of the word ditto?
The only five letter word that can be made with those letters is 'ditto'.Other words that can be made with the letters in 'ditto' are:dodotIidittotot
How many different three letter permutations can be from the letter in the word clipboard?
There are 9 * 8 * 7, or 504, three letter permutations that can be made from the letters in the work CLIPBOARD.
How many different 5 letter arrangements can be formed from the letters in the word Danny?
The number of 5 letter arrangements of the letters in the word DANNY is the same as the number of permutations of 5 things taken 5 at a time, which is 120. However, since the letter N is repeated once, the number of distinct permutations is one half of that, or 60.
How many different 4-letter permutations can be formed from the letters in the word DECAGON?
The word "DECAGON" has 7 letters, with the letter "A" appearing once, "C" appearing once, "D" appearing once, "E" appearing once, "G" appearing once, "N" appearing once, and "O" appearing once. To find the number of different 4-letter permutations, we need to consider combinations of these letters. Since all letters are unique, the number of 4-letter permutations is calculated using the formula for permutations of n distinct objects taken r at a time: ( P(n, r) = \frac{n!}{(n-r)!} ). Here, ( n = 7 ) and ( r = 4 ), so the number of permutations is ( P(7, 4) = \frac{7!}{(7-4)!} = \frac{7!}{3!} = 7 \times 6 \times 5 \times 4 = 840 ). Thus, there are 840 different 4-letter permutations that can be formed from the letters in "DECAGON."
How many 5 letter permutations can be formed from the letters in vertical?
There are 8P5 = 8*7*6*5*4 = 6720
How many different arrangements of 7 letters can be formed from the letters in the word ALGEBRA?
The number of 7 letter permutations of the word ALGEBRA is the same as the number of permutation of 7 things taken 7 at a time, which is 5040. However, since the letter A is duplicated once, you have to divide by 2 in order to find out the number of distinct permutations, which is 2520.
What is the number of distinguishable permutations of the letters in the word oregon?
360. There are 6 letters, so there are 6! (=720) different permutations of 6 letters. However, since the two 'o's are indistinguishable, it is necessary to divide the total number of permutations by the number of permutations of the letter 'o's - 2! = 2 Thus 6! ÷ 2! = 360
How many permutations of 5 letter can be made without any letters being repeated?
There are 7893600 permutations.
How many different ways are there to to scramble to letters of the word mass if s needs to be the first letter?
The number of permutations of the letters MASS where S needs to be the first letter is the same as the number of permutations of the letters MAS, which is 3 factorial, or 6. SMAS SMSA SAMS SASM SSMA SSAM
What is the number of two letter permutations of the letters rib?
Six.
