there is an infinite number. since numbers go on forever, theres always going to be a number greater than the last one divisible by both that is also divisible by both. i would tell you the least common multiple of them but im too lazy to figure it out. but you may have misphrased the question. 36 and 56 have two divisors (or factors) in common: 1 (times 36 and 56) and 4 (times 9 and 14). :)
56 is divisible by: 1, 2, 4, 7, 8, 14, 28, 56.
It is not as 6 is not a factor of 56.No, 56 is not divisible by 6.
The numbers that are divisible by 56 are in the form 56k where k is the integer constant.
56 of them.
The numbers that are divisible by 28 are infinite. The first four are: 28, 56, 84, 112 . . .
Here are several numbers that are divisible by 4: 4, 8, 12, 16, 20, 24, 28, 32, 36, 40, 44, 48, 52, 56, 60, ..., 100, 104, 108, ..., 400, 404, ...
8, 7, 2, 28
1x56 2x56 3x56 etc.
24, 32, 40, 48, 56
21, 28, 35, 42, 49, 56
The numbers that are divisible by four are infinite but here are the first 15: 4, 8, 12, 16, 20, 24, 28, 32, 36, 40, 44, 48, 52, 56, 60.
56, 64, 72, 80, 88, 96.