The answer is 6P5 = 6!/(6-5)! = 6*5*4*3*2*1/1 = 720
There are 5,273,912,160 permutations of 5 numbers out of 90.
Assuming you mean permutations of three digits, then the set of numbers that can be made with these digits is: 345 354 435 453 534 543 There are six possible permutations of three numbers.
Oh, dude, let's see. So, to calculate the number of permutations for 6789, you just multiply the number of options for each position. Since there are 4 numbers, you'd do 4! (4 factorial) which is 4 x 3 x 2 x 1, giving you a total of 24 permutations. Like, that's it. Piece of cake.
10! permutations of the word "Arithmetic" may be made.
The only five letter word that can be made with those letters is 'ditto'.Other words that can be made with the letters in 'ditto' are:dodotIidittotot
There are 7893600 permutations.
If repetition is allowed and order is important, then you have essentially a base-4 number system, with the numbers ranging from 00004 to 33334. The quantity of permutations in this example is 44 = 256. If repetition is not allowed, but order is important, then it is 4! = 24. * * * * * The above answer is perfectly correct. But, as stated in the answer, for permutations. However, according to the mathematical definition of combinations (as opposed to permutations), the order is irrelevant to combinations. 1234 is the same as 1423 or 4213 etc. Consequently, there can be only one 4-number combination from 4 numbers
There are 24 number made by permutations of the digits. There are lots more if the digits can be repeated, for example, 27335722. Even more can be made by using arithmetic and algebraic operations, for example 35^27 = approx 4.8960*10^41. You have not specified what the rules for "making" numbers are!
act
90000
is that four numbers or five numbers in serial number ?????
All the numbers from 0 to 999 so 1000 numbers However if you mean only using each number once the answer is about 720 * * * * * No. The above answer refers to the number of permutations. Permutations are NOT the same as combinations as anyone who has studies any probability theory can tell you. The number of combinations is 9C3 = 9*8*7/3*2*1 = 84