Assuming you mean permutations of three digits, then the set of numbers that can be made with these digits is: 345 354 435 453 534 543 There are six possible permutations of three numbers.
All of them.
8 digits will generate over 40,000 permutations.
Six - assuming 0123 does not count ... 1234 2345 3456 4567 5678 6789
If you mean permutations of the letters in the word "obfuscation", the answer is 1,814,400.
How many 3 diget number can made by the the following numbers 6789
There are 5,273,912,160 permutations of 5 numbers out of 90.
There are 7 factorial, or 5040 permutations of the letters in the word NUMBERS.
Assuming you mean permutations of three digits, then the set of numbers that can be made with these digits is: 345 354 435 453 534 543 There are six possible permutations of three numbers.
With 4 different numbers, 24.
All of them.
10! permutations of the word "Arithmetic" may be made.
The answer is 6P5 = 6!/(6-5)! = 6*5*4*3*2*1/1 = 720
There are 7893600 permutations.
act
8 digits will generate over 40,000 permutations.
This is permutations with repetition. The answer is 4^4 = 256 total permutations. Since 2 of the digits used are odd (and 2 are even), then half of the possibilities will be odd: 128 odd numbers.