The maximum is 10C2 = 10*9/(2*1) = 45
If no pair of lines is parallel and if each pairwise intersection is distinct, there will be 10 points of intersection.
Five intersecting lines can have a maximum of 10 points of intersection, assuming that no two lines are parallel and no three lines intersect at the same point. Each pair of lines can intersect at one unique point, and the number of ways to choose 2 lines from 5 is given by the combination formula ( \binom{5}{2} = 10 ). Therefore, with optimal conditions, the maximum number of intersection points is 10.
5 x 5 equels 10
the parallel lines never intercept so they do not have any common points.
A five-point star has 10 lines of symmetry. Each of the five points can be mirrored across a line that runs through the opposite point and the center of the star, resulting in five lines. Additionally, there are five lines that bisect the angles between the points, leading to a total of 10 lines of symmetry.
There are 91 lines.
10 lines, but only if no three of them are collinear.
there are 6 lines can pass through 4 noncollinear points.
10
Through any two distinct points, exactly one line can be drawn. For 5 non-collinear points, each pair of points can form a line. The number of ways to choose 2 points from 5 is given by the combination formula ( \binom{5}{2} ), which equals 10. Therefore, 10 lines can be drawn through 5 non-collinear points.
There are 20 common points.
If only 7 are colinear, then the question implies the lines need not go through every point. In that case there is an infinity of lines for each point.