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How many possibilities are there with the four digit numbers 0000-9999 while the first number cannot be 0 or 9?
Wiki User
∙ 11y ago
The first digit can be any one of 8. For each of these . . .
The second digit can be any one of 10. For each of these . . .
The third digit can be any one of 10. For each of these . . .
The fourth digit can be any one of 8.
Total possibilities = (8 x 10 x 10 x 8) = 6,400
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∙ 11y ago
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How many three digit numbers have three distinct digits?
For a 3 digit number, the left most or the most significant digit cannot be zero. So it can be 1,2,3,4,5,6,7,8 or 9 which is 9 possibilities. The middle number can be 0,1,2,3,4,5,6,7,8,9 which is 10 possibilties but one of the digits has been chosen already as the first digit, so the possibilities are only 9. The right most number can be 0,1,2,3,4,5,6,7,8,9 which is 10 possibilities but two of the digits have been already used by the left most and the middle digits. That leaves only 8 possibilities. So the total number of three digit numbers that have three distinct digits is 9 x 9 x 8 = 81 x 8 = 648 possibilities
All seven-digit telephone numbers in a town begin with 245 how many telephone numbers may be assigned in the town if the last 4 digits do not begin or end in a zero?
There are seven positions: _ _ _ _ _ _ _ Each must be filled by number 0-9 and numbers can be repeated. The first three positions must be 2,4,5, therefore, 2 4 5 _ _ _ _ For the other for positions, the 4th and 7th position cannot be 0 (therefore only 9 possibilities: 1-9) and the 5th and 6th position can be any number (10 possibilities: 0-9). Therefore, the total number of possibilities is 9 * 10 * 10 * 9 = 8100 since the positions are independent.
Numbers 0-9 how many different 13 digit combination can be made?
10,000,000,000,000 This would be the number of permutations on a 13-position combination lock, for example. In the first position there would be one number out of ten possibilities (0-9). Next to any one number there would be any one of ten again. So in the first two positions there are 10 x 10 possible combinations i.e. 10^2 (= 100). In the third position there would be 10 more possibilities against the previous 100 possibilities, i.e. 100 x 10, that is: 10^3 (= 1000). So, for a thirteen digit lock, there would be 10^13 possibilities, which is 1 followed by thirteen zeros, as shown above. Of course, if 'numbers' with leading digits e.g. 0 000 087 654 321, and all zeros, are not counted as valid 'numbers' then there are 13 less possibilities. i.e. There are only 9,999,999,999,987 possible ' numbers'.
I need 5 numbers to go with it to average 53 what are they?
There are an unlimited number of possibilities. If you need five consecutive whole numbers, that's different, your answer would b e 51, 52, 53, 54, and 55.
How many four digits numbers can be formed using 0123456789?
Assuming that the first digit of the 4 digit number cannot be 0, then there are 9 possible digits for the first of the four. Also assuming that each digit does not need to be unique, then the next three digits of the four can have 10 possible for each. That results in 9x10x10x10 = 9000 possible 4 digit numbers. If, however, you can not use the same number twice in completing the 4 digit number, and the first digit cannot be 0, then the result is 9x9x8x7 = 4536 possible 4 digit numbers. If the 4 digit number can start with 0, then there are 10,000 possible 4 digit numbers. If the 4 digit number can start with 0, and you cannot use any number twice, then the result is 10x9x8x7 = 5040 possilbe 4 digit numbers.
How many combinations are there in 39 numbers?
It depends on how many numbers are in each combination. If there are 5 numbers in each combination, then you have 575,757 possibilities. If there are 2 in each combination, there you have 741 possibilities. If there's only 1 number in each combination, then there are only 39 possibilities.
What two numbers can be divided by 108?
Two of the infinite number of possibilities, are: 108000 and 108000000000000
What square numbers are there before 100 which are prime numbers?
A square number, by definition, cannot be a prime so the answer is there are no such numbers.A square number, by definition, cannot be a prime so the answer is there are no such numbers.A square number, by definition, cannot be a prime so the answer is there are no such numbers.A square number, by definition, cannot be a prime so the answer is there are no such numbers.
If A standard combination lock has 60 numbers on its face from 0 to 59 a combination consits of three numbers and numbers can be repeated what is the total number of possible combinations?
There are 60 possible numbers for the first number, A, in the combination (1,2,3,...,59,60).For each of outcome of A, there are 60 outcomes for the second number, B, giving a two digit combination 60x60=360 possibilities.For each of these 360 outcomes, there are 60 outcomes for the third number, C, making the number of possible combinations 360x60=21600.Or 60 possibilities x 60 possibilities x 60 possibilities = 21,600 possibilities.
Is an irrational number cannot be a real number?
Irrational numbers are real numbers.
How many three digit numbers have three distinct digits?
For a 3 digit number, the left most or the most significant digit cannot be zero. So it can be 1,2,3,4,5,6,7,8 or 9 which is 9 possibilities. The middle number can be 0,1,2,3,4,5,6,7,8,9 which is 10 possibilties but one of the digits has been chosen already as the first digit, so the possibilities are only 9. The right most number can be 0,1,2,3,4,5,6,7,8,9 which is 10 possibilities but two of the digits have been already used by the left most and the middle digits. That leaves only 8 possibilities. So the total number of three digit numbers that have three distinct digits is 9 x 9 x 8 = 81 x 8 = 648 possibilities
What are all the paired numbers with 70 as its lcm?
35 and 70 is one of an infinite number of possibilities.
What number is any rational or irrational number?
Rational numbers are numbers that can be written as a fraction. Irrational numbers cannot be expressed as a fraction.
What 2 numbers can be multiplied to get 63?
There are an infinite number of possibilities. If you only want to talk about positive whole numbers, then there are 3 possibilities: 1 x 63 3 x 21 7 x 9
Why are the multiples of any number other than one not prime numbers?
The multiples of any number cannot be prime numbers because such numbers are the product of at least two numbers. Prime numbers, but definition, cannot be cannot be the product of any numbers except itself and one.
How many 7 digit telephone numbers can be formed if the first three digits cannot be 800 and the first digit cannot be 0?
There are nine possibilities for the first digit. If this digit is not 8, there are ten possibilities for each of the remaining digits. Thus, if the first digit is not 8, there are 8 X 106 possibilities. If the first digit is 8, there are only nine choices for the second and third digits, since zero is excluded. This gives 9 X 9 X 104 possibilities that begin with 8. The total number of possibilities is therefore the sum of these two possibilities, which is 9.81 X 106 = 9,810,000.
How do you figure out what is the number of the number cube?
You cannot. And not all number cubes have the numbers 1-6 on them. For example, a doubling cube for backgammon.You cannot. And not all number cubes have the numbers 1-6 on them. For example, a doubling cube for backgammon.You cannot. And not all number cubes have the numbers 1-6 on them. For example, a doubling cube for backgammon.You cannot. And not all number cubes have the numbers 1-6 on them. For example, a doubling cube for backgammon.
