The first digit can be any one of 8. For each of these . . .
The second digit can be any one of 10. For each of these . . .
The third digit can be any one of 10. For each of these . . .
The fourth digit can be any one of 8.
Total possibilities = (8 x 10 x 10 x 8) = 6,400
For a 3 digit number, the left most or the most significant digit cannot be zero. So it can be 1,2,3,4,5,6,7,8 or 9 which is 9 possibilities. The middle number can be 0,1,2,3,4,5,6,7,8,9 which is 10 possibilties but one of the digits has been chosen already as the first digit, so the possibilities are only 9. The right most number can be 0,1,2,3,4,5,6,7,8,9 which is 10 possibilities but two of the digits have been already used by the left most and the middle digits. That leaves only 8 possibilities. So the total number of three digit numbers that have three distinct digits is 9 x 9 x 8 = 81 x 8 = 648 possibilities
There are seven positions: _ _ _ _ _ _ _ Each must be filled by number 0-9 and numbers can be repeated. The first three positions must be 2,4,5, therefore, 2 4 5 _ _ _ _ For the other for positions, the 4th and 7th position cannot be 0 (therefore only 9 possibilities: 1-9) and the 5th and 6th position can be any number (10 possibilities: 0-9). Therefore, the total number of possibilities is 9 * 10 * 10 * 9 = 8100 since the positions are independent.
10,000,000,000,000 This would be the number of permutations on a 13-position combination lock, for example. In the first position there would be one number out of ten possibilities (0-9). Next to any one number there would be any one of ten again. So in the first two positions there are 10 x 10 possible combinations i.e. 10^2 (= 100). In the third position there would be 10 more possibilities against the previous 100 possibilities, i.e. 100 x 10, that is: 10^3 (= 1000). So, for a thirteen digit lock, there would be 10^13 possibilities, which is 1 followed by thirteen zeros, as shown above. Of course, if 'numbers' with leading digits e.g. 0 000 087 654 321, and all zeros, are not counted as valid 'numbers' then there are 13 less possibilities. i.e. There are only 9,999,999,999,987 possible ' numbers'.
There are an unlimited number of possibilities. If you need five consecutive whole numbers, that's different, your answer would b e 51, 52, 53, 54, and 55.
Assuming that the first digit of the 4 digit number cannot be 0, then there are 9 possible digits for the first of the four. Also assuming that each digit does not need to be unique, then the next three digits of the four can have 10 possible for each. That results in 9x10x10x10 = 9000 possible 4 digit numbers. If, however, you can not use the same number twice in completing the 4 digit number, and the first digit cannot be 0, then the result is 9x9x8x7 = 4536 possible 4 digit numbers. If the 4 digit number can start with 0, then there are 10,000 possible 4 digit numbers. If the 4 digit number can start with 0, and you cannot use any number twice, then the result is 10x9x8x7 = 5040 possilbe 4 digit numbers.
It depends on how many numbers are in each combination. If there are 5 numbers in each combination, then you have 575,757 possibilities. If there are 2 in each combination, there you have 741 possibilities. If there's only 1 number in each combination, then there are only 39 possibilities.
A square number, by definition, cannot be a prime so the answer is there are no such numbers.A square number, by definition, cannot be a prime so the answer is there are no such numbers.A square number, by definition, cannot be a prime so the answer is there are no such numbers.A square number, by definition, cannot be a prime so the answer is there are no such numbers.
Irrational numbers are real numbers.
Two of the infinite number of possibilities, are: 108000 and 108000000000000
There are 60 possible numbers for the first number, A, in the combination (1,2,3,...,59,60).For each of outcome of A, there are 60 outcomes for the second number, B, giving a two digit combination 60x60=360 possibilities.For each of these 360 outcomes, there are 60 outcomes for the third number, C, making the number of possible combinations 360x60=21600.Or 60 possibilities x 60 possibilities x 60 possibilities = 21,600 possibilities.
Rational numbers are numbers that can be written as a fraction. Irrational numbers cannot be expressed as a fraction.
35 and 70 is one of an infinite number of possibilities.
The multiples of any number cannot be prime numbers because such numbers are the product of at least two numbers. Prime numbers, but definition, cannot be cannot be the product of any numbers except itself and one.
For a 3 digit number, the left most or the most significant digit cannot be zero. So it can be 1,2,3,4,5,6,7,8 or 9 which is 9 possibilities. The middle number can be 0,1,2,3,4,5,6,7,8,9 which is 10 possibilties but one of the digits has been chosen already as the first digit, so the possibilities are only 9. The right most number can be 0,1,2,3,4,5,6,7,8,9 which is 10 possibilities but two of the digits have been already used by the left most and the middle digits. That leaves only 8 possibilities. So the total number of three digit numbers that have three distinct digits is 9 x 9 x 8 = 81 x 8 = 648 possibilities
You cannot. And not all number cubes have the numbers 1-6 on them. For example, a doubling cube for backgammon.You cannot. And not all number cubes have the numbers 1-6 on them. For example, a doubling cube for backgammon.You cannot. And not all number cubes have the numbers 1-6 on them. For example, a doubling cube for backgammon.You cannot. And not all number cubes have the numbers 1-6 on them. For example, a doubling cube for backgammon.
Rational numbers are numbers that can be written as a fraction. Irrational Numbers cannot be expressed as a fraction. Any number that is a fraction is not an integer, but rational.
Prime numbers cannot be square numbers.