Here are three possible interpretations of the question, with answers:
A) How many combinations are possible when when rolling three identical regular dice simultaneously, if all the dice show an even number?
Answer: 10 (Originally given by Mehta matics)
... (2,2,2) -> 6
... (2,2,4) -> 8
... (2,2,6), (2,4,4) -> 10
... (2,4,6), (4,4,4) -> 12
... (2,6,6), 4,4,6) -> 14
... (4,6,6) -> 16
... (6,6,6)-> 18
B) How many combinations result in an even total when rolling three identical regular dice simultaneously?
Answer:28
... The totals must be between 3 and 18 inclusive.
... sum of 4: (1,1,2)
... sum of 6: (1,1,4), (1,2,3), (2,2,2)
... sum of 8: (1,1,6), (1,2,5), (1,3,4), (2,2,4), (2,3,3)
... sum of 10: (1,3,6), (1,4,5), (2,2,6), (2,3,5), (2,4,4), (3,3,4)
... sum of 12: (1,5,6), (2,4,6), (2,5,5), (3,3,6), (3,4,5), (4,4,4)
... sum of 14: (2,6,6), (3,5,6), (4,4,6), (4,5,5,)
... sum of 16: (4,6,6), (5,5,6)
... sum of 18: (6,6,6), for a total of 1+3+5+6+6+4+2+1 =28 combinations.
C) When rolling three regular dice, how many even totals are possible?
Answer: 8
... 4, 6, 8, 10, 12, 14, 16, 18.
If you have 12 possible numbers with multiple combinations then you should start out with making all the possible combinations; you will find theyre 20. Theyre four numbers out of the twleve that can be divisible by three; 3, 6, 9, and 12. There are 7 combinations where the combinations can equal those four numbers. So the odds of getting a sum divisible by three is 7/20.
one die, the numbers 1,2,3,4,5 or 6, two dice, the 1,1 1,2 1,3 1,4 1,5 1,6 2,1 etc. There are 36 outcomes
15/21= 71.43% chance. It's the number of possible throws without repetition divided by the total different combinations of dice throw. Here is a handy Combination and Permutation Calculator: http://www.mathsisfun.com/combinatorics/combinations-permutations-calculator.html
There are 6 possible numbers that can be rolled. "4" is one of those possible numbers. Probability is therefore 1/6.
48
If you have 12 possible numbers with multiple combinations then you should start out with making all the possible combinations; you will find theyre 20. Theyre four numbers out of the twleve that can be divisible by three; 3, 6, 9, and 12. There are 7 combinations where the combinations can equal those four numbers. So the odds of getting a sum divisible by three is 7/20.
one die, the numbers 1,2,3,4,5 or 6, two dice, the 1,1 1,2 1,3 1,4 1,5 1,6 2,1 etc. There are 36 outcomes
15/21= 71.43% chance. It's the number of possible throws without repetition divided by the total different combinations of dice throw. Here is a handy Combination and Permutation Calculator: http://www.mathsisfun.com/combinatorics/combinations-permutations-calculator.html
There are 6 possible numbers that can be rolled. "4" is one of those possible numbers. Probability is therefore 1/6.
48
The answer is 12 APEX ✨
There are 8 possible combinations that would produce a 5 or 9 and 8/36=2/9.
The probability of rolling a 9 with two dice is 4/36 or 1/9. There are 36 possible combinations and a 9 is obtained by rolls of 3,6; 4,5; 6,3; & 5,4.
Of the 36 possible combinations rolling two dice there are 2 combinations that add up to 11 so the odds are 18:1
The chance is 1/36. (There are 36 possible combinations for two 6-sided dice, but only 18 separate combinations when the dice are not considered seperately.)
11 = 6+5 is the only solution, so there are two combinations first dice : 6, second dice : 5 first dice : 5, second dice : 6
If the numbers (or symbols) are all different then 10 outcomes.