heads and tails
When you toss a 6-sided die 7 times, each toss has 6 possible outcomes. Since the tosses are independent, you can calculate the total number of outcomes by raising the number of outcomes per toss to the power of the number of tosses: (6^7). This equals 279,936 possible outcomes.
Each toss has 2 outcomes; so the number of outcomes for 3 tosses is 2*2*2 = 8
2x2x2=8 possible outcomes. In general for n tosses there are 2^n outcomes.
It depends on the definition of an outcome. If you care about the order of the tosses, <br /> you get 2 possible outcomes per toss. Three tosses give you 2*2*2=8 possible outcomes. If you only care about the final number of heads and tails, there are 4 possible outcomes (3 heads, 2 heads and a tail, a head and two tails, or 3 tails).
2 sides x 10 tosses, so your possibilities is 2^10 or 2x2x2x2x2x2x2x2x2x2 =1024 outcomes.
There are 2 possibilities for each toss. Since the three tosses are independent (one trial does not affect the outcome of the other trials), there are 2 * 2 * 2 = 8 total possible outcomes. The outcomes are: HHH HHT HTH HTT THH THT TTH TTT
There are 36 possible outcomes: 6 for each die.
For a coin toss, there are 2 possible outcomes (heads or tails). For five tosses, therefore, there are 25 possible outcomes (25 = 32). However, this assumes that order is important (i.e. that HtttH is different to tHtHt). If you don't care what order the heads or tails fall in, there are only 6 outcomes.
Two possible outcomes for each flip. 2,048 possible histories of 11 flips.
We use three coins (quarter, nickel, dime) each are flipped only once. We get 8 possible outcomes (or four outcomes as an alternative).
To determine the amount of possible outcomes, there must be a number of sections for each spinner
There are 12.