We use three coins (quarter, nickel, dime) each are flipped only once. We get 8 possible outcomes (or four outcomes as an alternative).
There are two outcomes for each coin and three coins; 2 x 2 x 2 = 23 = 8 outcomes.
enless you include it landing on it's side the two possible outcomes for this are: Heads and Tails
If a normal die is rolled once, the outcomes are {1, 2, 3, 4, 5, 6}.
Each coin can come out either heads (H) or tales (T). Since you're tossing four coins at once, I'm assuming there is no sense of order to be accounted for. In that case, the possible outcomes are the following: HHHH HHHT HHTT HTTT TTTT
We use three coins (quarter, nickel, dime) each are flipped only once. We get 8 possible outcomes (or four outcomes as an alternative).
There are 12.
There are eight (8).
There are two outcomes for each coin and three coins; 2 x 2 x 2 = 23 = 8 outcomes.
enless you include it landing on it's side the two possible outcomes for this are: Heads and Tails
Assuming it is a 6-sided number cube, it would be 6.
If a normal die is rolled once, the outcomes are {1, 2, 3, 4, 5, 6}.
Since each coin would have the outcome with Heads and Tails: Then among the 32 coins, we can have the possible outcomes from no Heads, 1 Head, 2 Heads, ....... , 31 Heads, 32 Heads. Therefore we would have 33 outcomes.
A system with two possible outcomes with equal probabilities.
2*2*6 = 24 outcomes.
If you know which coin is which, there are 16possible outcomes.If you're only counting the number of Heads and Tails, there are 5 .
Each coin can come out either heads (H) or tales (T). Since you're tossing four coins at once, I'm assuming there is no sense of order to be accounted for. In that case, the possible outcomes are the following: HHHH HHHT HHTT HTTT TTTT