For a coin toss, there are 2 possible outcomes (heads or tails). For five tosses, therefore, there are 25 possible outcomes (25 = 32). However, this assumes that order is important (i.e. that HtttH is different to tHtHt). If you don't care what order the heads or tails fall in, there are only 6 outcomes.
Since there are 2 outcomes for a coin toss, and you will toss the coin 3 times the number of outcomes are 23 or 8. Since H-T-H can occur only 1 way, the probability of the H-T-H sequence is 1/8.
There are 12 possible outcomes.
There are 4 possible outcomes. There are 2 outcomes (heads or tails) on the first toss and 2 on the second toss. The possibilities are HH, TT, HT and TH.
4
all headsall tails3 heads 1 tail3 tails and 1 head2h and 2ti think only 5 but that's just what i can get===============================================The above answer is correct if you disregard the order of the outcomes.If the order of the outcomes matters, then the answer is:2 x 2 x 2 x 2 = 16since each toss has two possible outcomes (assuming the coin cannot land on its side) and you repeat the toss four times.
3
24 or 16
Two
2^4 = 16
2x2x2=8 possible outcomes. In general for n tosses there are 2^n outcomes.
Two times the number of outcomes of the spin - which is not specified in the question.
eight
Each toss has 2 outcomes; so the number of outcomes for 3 tosses is 2*2*2 = 8
Since there are 2 outcomes for a coin toss, and you will toss the coin 3 times the number of outcomes are 23 or 8. Since H-T-H can occur only 1 way, the probability of the H-T-H sequence is 1/8.
when you toss a coin three times, the total number of possible outcomes is
There are 12 possible outcomes.
2*2*6 = 24 outcomes.