If the new mixture is 40% juice then it is 60% water.
The ratio of juice to water is therefore 40 : 60 = 2 : 3
So, for every 2 parts juice then 3 parts water are needed.
2 gallons of juice then requires 3 gallons of water.
3 gallons water = 3 x 4 = 12 quarts water.
5.6 quarts
2 gallons.
50 gallons @ 3% must be added.
132 gallons 16 : 84 of 60 gallons = 9.6 : 50.4 gallons 80 : 20 of 132 gallons = 105.6 : 26.4 gallons added = 115.2 : 76.8 gallons = 1.5:1 ( 60:40)
0.25 gallons of water (or 1 quart)
NO AFENCE, BUT THAT IS AN IMPOSIPLE QUESTION TO ANSWER. MAYBE SOMEONE WILL ANSWER THAT FOR YOU. GOOD LUCK!
4.2 quarts
millions of gallons
If my math is correct it would take an additional ( .6 of a U.S. quart of antifreeze ) to increase a 30 % antifreeze volume to 40 % if the total volume of the mixture is 6 quarts
First off do not use tap water. Use only distilled water. You will need to add 3 gallons of distilled water to the solution to get 60% antifreeze and 40% distilled water or a 60/40 mix.
The original solution has 3.6 quarts of antifreeze in it. The equation then becomes (3.6 + x)/(12 + x) = 0.40, where x is the amount of antifreeze added. X is then equal to 2.
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