There are an infinite number of them.
Here are a few:
0.5 x 32
0.8 x 20
1 x 16
1.6 x 10
2 x 8
2.5 x 6.4
4 x 4
Pick any number you want for the rectangle's length. We'll call your number ' L '.
Now I'll pick the width of the rectangle. It's ( 16 / L ).
The rectangle's area is 16, and there's no limit to how many different ways
we can play this game.
thare is only 1 differint rectangles
The answer is Infinite...The rectangles can have an infinitely small area and therefore, without a minimum value to the area of the rectangles, there will be an uncountable amount (infinite) to be able to fit into that 10 sq.in.
18x1 9x2 6x3
Infinitely many.
3
9
Factors of 36 are 1, 2, 3, 4, 6, 9, 12, 18, and 36. So, there are 5 rectangles with an area of 36 cm^2 is 5.
You could consider the cross as two intersecting rectangles. Calculate the area of both rectangles and the area of the intersection (overlap). Then area of cross = sum of the areas of the rectangles minus the area of the overlap.
123x123=123
13
As many as you want, if they are small enough!
To determine the number of smaller rectangles in an area model representing 27 x 83, you would multiply the number of smaller rectangles along the length and width. In this case, there are 27 smaller rectangles along the length and 83 smaller rectangles along the width. Multiplying these numbers together gives you a total of 27 x 83 = 2241 smaller rectangles in the area model.