To find the perimeter of a square with a diagonal of 16 cm, we first need to determine the side length of the square using the Pythagorean theorem. The diagonal of a square divides it into two right-angled triangles, with the diagonal being the hypotenuse. Using the formula a^2 + b^2 = c^2, where a and b are the two sides of the triangle and c is the hypotenuse, we can calculate that each side of the square is 8√2 cm. Since a square has four equal sides, the perimeter is 4 times the side length, giving us a perimeter of 32√2 cm.
A triangle with side a: 7, side b: 7, and side c: 7 cm has an area of 21.22 square cm.
Pythagorean theorem: Usually revolves around the hypotenuse side of a triangle [The side opposite the right angle]. What you do is, You look at the length of all the sides. If Side A [the hypotenuse] Is 8cm long, side B is 3 cm long and side C is 4 cm long. Then what you do is, use this rule. A squared = B squared + c squared. Which basically means, get the lengths of the two sides that are NOt the hypotenuse. Square them. Add them together. Then square root your answer. For example, the answer to: If Side A [the hypotenuse] Is 8cm long, side B is 3 cm long and side C is 4 cm long is: 8x8=64. 3x3=9. 64+9=53. Square route of 53 = 7.28 [rounded] So basically, Square B and C, add them together, square root it to get the length of the hypotenuse
Memorize KHDBdcm B=>base unit. put the 3 of 13 in the base value. Move the decimal to the c place which is two places. 1300 cm
Miguel has a square. From the information we know that the side length of the square is 12 cm. Since we are dealing with a square, we know all sides are 12 cm. Miguel cuts the square along the diagonal. Miguel now has two right triangles. We know that two sides of each of the right triangles have lengths of 12 cm. We don't know what the other side (diagonal side) is, so we must use the Pythagorean Theorem a2 + b2 = c2 Let side one be "a" and side two be "b", "c" will be the diagonal side. 122 + 122 = c2 144 + 144 = c2 √288 = c2 The square root of 288 is 16.97 Now we know that the perimeter equals 12+12+16.97 = 40.97 cm 40.97 rounded to the nearest tenth equals 41.0 cm
A triangle with side a: 2, side b: 2, and side c: 2 cm has an area of 1.73 square cm.
A triangle with side a: 7, side b: 7, and side c: 5 cm has an area of 16.35 square cm.
The correct answer is 10 times the square of 2. You must use the Pythagorean Theorem, which is a2+b2=c2. The sides if the square measure 10 cm because adding all four sides will give you the perimeter of 40 cm. Replace a and b with 10 and solve for c.
A triangle with side a: 8, side b: 11, and side c: 15 cm has an area of 42.85 square cm.
Using trigonometry its smallest angle is 43.84 degrees and its area is 18.2 square cm--------------------------------------Using the cosine rule to find the angle:a² = b² + c² - 2bc cos A→ cos A = (b² + c² - a²)/(2bc)→ A = arccos ((6.4² + 8.2² - 5.7²)/(2 × 6.4 × 5.7)) ≈ 43.8°Area = ½ × b × c × sin A ≈ ½ × 6.4 cm × 8.2 cm × sin 43.8° ≈ 18.2 cm²
Using the sine formulae of a/A=b/B=c/C and A/a=B/b=C/c in trigonometry the perimeter of the triangle is 31.08 cm with a height of 2.76 cm both rounded to two decimal places.
C=2 pi r C = 2 * 3.14 * 3.5 cm C= 21.98 cm