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Miguel is making a stained glass window He cuts a 12 cm square along the diagonal to create two right triangles Find the perimeter of each triangle to the nearest tenth of a centimeter and explain?
Gangel264
Miguel has a square. From the information we know that the side length of the square is 12 cm. Since we are dealing with a square, we know all sides are 12 cm.
Miguel cuts the square along the diagonal. Miguel now has two right triangles.
We know that two sides of each of the right triangles have lengths of 12 cm. We don't know what the other side (diagonal side) is, so we must use the Pythagorean Theorem
a2 + b2 = c2
Let side one be "a" and side two be "b", "c" will be the diagonal side.
122 + 122 = c2
144 + 144 = c2
√288 = c2
The square root of 288 is 16.97
Now we know that the perimeter equals 12+12+16.97 = 40.97 cm
40.97 rounded to the nearest tenth equals 41.0 cm
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