The first digit has to be in the set [1-6] because, if it were zero, it would not be a three digit number. The number of combinations, not using duplicates, of three numbers from the set [0-6] is 6 times 6 times 5, or 180.
30 EX: for one: 124,134,154,132,152,142. so 5 multiple 6=30 :)
18 of them.
If you don't repeat, 20. If you do, 58.
99999
210 of them.
5040 different 4 digit numbers can be formed with the digits 123456789. This is assuming that no digits are repeated with each combination.
8.
There are 900 of them.
Assuming each of the given digits can be used only once, the answer is 24. If not, the answer is infinity.
One example! 4 × 5 × 6 × 7 − 9 = 831 -------- I disagree with this answer. Three digits can be chosen from five in 5C3 = 10 ways For each of these choices the three digits can be ordered in 6 ways. Therefore, 10(6) = 60 numbers can be formed.
30 EX: for one: 124,134,154,132,152,142. so 5 multiple 6=30 :)
18 of them.
48 of them if digits may not be repeated. 100 if they can.
None, because you do not have three even digits. None, because you do not have three even digits. None, because you do not have three even digits. None, because you do not have three even digits.
Assuming you mean permutations of three digits, then the set of numbers that can be made with these digits is: 345 354 435 453 534 543 There are six possible permutations of three numbers.
If the digits can be used more than once, then 900. If not, then 648.
Two in each big toe and three in the 4 remaining digits