Q: How many three digits can be formed from the digits 0 1 2 3 4 5 and 6 if each digits can be used only once?

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30 EX: for one: 124,134,154,132,152,142. so 5 multiple 6=30 :)

18 of them.

If you don't repeat, 20. If you do, 58.

99999

210 of them.

Related questions

8.

There are 900 of them.

There are 7,290 different 4-digit numbers that can be formed from the digits 1-9 without repetition.

One example! 4 × 5 × 6 × 7 − 9 = 831 -------- I disagree with this answer. Three digits can be chosen from five in 5C3 = 10 ways For each of these choices the three digits can be ordered in 6 ways. Therefore, 10(6) = 60 numbers can be formed.

30 EX: for one: 124,134,154,132,152,142. so 5 multiple 6=30 :)

18 of them.

None, because you do not have three even digits. None, because you do not have three even digits. None, because you do not have three even digits. None, because you do not have three even digits.

48 of them if digits may not be repeated. 100 if they can.

Assuming you mean permutations of three digits, then the set of numbers that can be made with these digits is: 345 354 435 453 534 543 There are six possible permutations of three numbers.

Two in each big toe and three in the 4 remaining digits

If the digits can be used more than once, then 900. If not, then 648.

720