7 two-digit numbers.
The sum of all palindromic numbers from 1001 to 9999 is 495000.
The same as the number of two-digit numbers, since the last two digits must the same as the first two, only reversed. So I'll say there are 100 four-digit palindromes.
The same as the number of two-digit numbers, since the last two digits must the same as the first two, only reversed. So I'll say there are 100 four-digit palindromes.
With 123 digits you can make 123 one-digit numbers.
There are 9 digits that can be the first digit (1-9); for each of these there is 1 digit that can be the second digit (6); for each of these there are 10 digits that can be the third digit (0-9); for each of these there are 10 digits that can be the fourth digit (0-9). → number of numbers is 9 × 1 × 10 × 10 = 900 such numbers.
If the number with the digits reversed can have a leading 0 so that it is a 1-digit number, then 16. Otherwise 13.
The sum of all palindromic numbers from 1001 to 9999 is 495000.
47 Impossible problem!
Find a four digit number whose digits will be reversed when multiplied by nine?
The same as the number of two-digit numbers, since the last two digits must the same as the first two, only reversed. So I'll say there are 100 four-digit palindromes.
The same as the number of two-digit numbers, since the last two digits must the same as the first two, only reversed. So I'll say there are 100 four-digit palindromes.
The number you are looking for is 12. Reversing the digits gives you 21 75% of 12 is 9 12 + 9 = 21
Possibility of two digit no whose sum is 9 18,27,36,45,54,63,72,81 Now add 63 to each no mentioned above output is 81,90,99,108,117,126,135,144 See 18 and 81. If you reverse 18 . 81 will come which is the no increased by 63. 18 is
With 123 digits you can make 123 one-digit numbers.
An eight digit number with one zero cannot remain the same when its digits are reversed. It must have an even number of 0s.
There are 5460 five digit numbers with a digit sum of 22.
There are 9 digits that can be the first digit (1-9); for each of these there is 1 digit that can be the second digit (6); for each of these there are 10 digits that can be the third digit (0-9); for each of these there are 10 digits that can be the fourth digit (0-9). → number of numbers is 9 × 1 × 10 × 10 = 900 such numbers.