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That would be the number of possible combinations of men, multiplied by the number of possible combinations of men. For each subset, the total number of possible combinations will be the factorial of the number available, divided by the factorial of that number minus six. In other words:

x = 10!/(10 - 6)! * 12!/(12-6)!

âˆ´ x = 10!/4! * 12!/6!

âˆ´ x = (10 * 9 * 8 * 7 * 6 * 5) * (12 * 11 * 10 * 9 * 8 * 7)

âˆ´ x = 151200 * 665280

âˆ´ x = 100590336000

So there are one hundred billion, five-hundred-and-ninety million, three-hundred-and-thirty-six thousand possible jury combinations from that selection.

Q: How many ways can a jury of 6 men and 6 women be selected from 10 women and 12 men?

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The number of ways is 18C5 = 18!/(5!*13!) = 8,568 ways.

There are 8!/(4!*4!) = 70 ways.

The number is 30C3 = 30!/[3!*(30-3)!] = 30*29*28/(3*2*1) = 4060

Three students can be selected from 5 in (5 x 4 x 3) = 60 ways.BUT there are (3 x 2) = 6 ways to select the same 3 students.So there are only 60/6 = 10 different groups of 3 studentsthat can be selected from a pool of 5.

30 = 6 * 5 if we assume the president and the vice-president must be different people.

Related questions

In how many ways can fourfour women be selected from the eighteight ​women

600600 First, find how many different combinations of men can there be, which is 330; and how many different combinations of women can there be, which is 1820. Then, multiply them together and you get 600600

24 ways to make this selection.

They can be selected in 756 ways.

Because he is races

If there are 58 defective circuit boards, two can be selected in 58*57/2 = 1653 ways.

If this was meant to be a math puzzle question then you don't know anything about picking juries. There's only ONE way of picking juries REGARDLESS of how many jurors are to be chosen. Picking jurors bears NO resemblance to a numbers game.

18x17= 306 ways

53,130 ways.

35

30240

The number of ways is 18C5 = 18!/(5!*13!) = 8,568 ways.