It can be just about any height. To get a specific answer, you would also have to know how high the Sun is in the sky - how many degrees above the horizon; and that can be anythiing between 0 and 90 degrees.
(18/16)x40=45
1. How high is a flagpole that casts a shadow of 45 ft at the same time a woman 5.5 ft tall casts a shadow 10 ft?
It is 2925 square feet.
20 feetAny height.When the Sun is low, in the morning or evening close to the horizon, even a short object will cast a long shadow. When the Sun is directly overhead (at noon between the Tropic of Capricorn and the Tropic of Cancer) objects cast no shadow.If you tell us your location and the time you are measuring then there would be a possibility of calculating an answer.At noon on one of the equinoxes in Montpelier VT (or anywhere at the latitude of 45 degrees north or 45 degrees south) a 50 foot tall tree will cast a 50 foot shadow.
That would depend on the angle of light on the tree.Any height.When the Sun is low, in the morning or evening close to the horizon, even a short object will cast a long shadow. When the Sun is directly overhead (at noon between the Tropic of Capricorn and the Tropic of Cancer) objects cast no shadow.If you tell us your location and the time you are measuring then there would be a possibility of calculating an answer.At noon on one of the equinoxes in Montpelier VT (or anywhere at the latitude of 45 degrees north or 45 degrees south) a 20 foot tall tree will cast a 20 foot shadow.
No way of telling, it depends on the angle of the sun.Any height.When the Sun is low, in the morning or evening close to the horizon, even a short object will cast a long shadow. When the Sun is directly overhead (at noon between the Tropic of Capricorn and the Tropic of Cancer) objects cast no shadow.If you tell us your location and the time you are measuring then there would be a possibility of calculating an answer.At noon on one of the equinoxes in Montpelier VT (or anywhere at the latitude of 45 degrees north or 45 degrees south) a 48 foot tall tree will cast a 48 foot shadow.
60 inches, or 5 feet.
Height of building/105 = 6/14 Multiply both sides by 105: Height = 630/14 Height = 45 feet
Suppose the length of the shadow is s metres. Then tan(62 deg) = 45/S so that S = 45/tan(62 deg) = 45/1.88 (approx = 23.93 metres, approx.
Let the height of the tree be x and use trigonometry and the tangent ratio: x/800 = 135/45 x = 2400 cm = 24 m
To convert 45 cm to foot, you can divide by 30.48 (since 1 foot is approximately 30.48 cm). So, 45 cm is roughly 1.48 feet.
1 floor is around 7.5 ft or so, which would be 45 ft tall