5.5/8 = x/20 x=5.5*20/8 = 13.75 feet
40 ft
50 feet
That all depends upon what time of day the shadow was cast. For example, at straight up noon, even a very tall building wouldn't cast much of a shadow, but at sunrise or sunset, even a tiny building might cast an 18 foot long shadow, or even longer.
The lenght of the shadow will be 12.6 ft
116
To cast a 19 foot shadow the building would have to be 26.91 feet tall. Each foot of building/tree casts 8.47 inches of shadow.
Not enough information has been given to solve this problem such as: What is the angle of elevation?
1.8 meters. The ratio of object to shadow is 10:6. Therefore if the object is 3, the shadow is 1.8 ( 6/10x3).
As the question is stated, Tom is standing IN THE TOWER'S SHADOW. If so, then Tom can't cast a shadow of his own, because he is not illuminated. Let's assume the question means to imply that Tom's shadow is measured AT THE SAME TIME that the shadow of the tower is measured, and kind of NEAR the tower, so that the sun casts both shadows from the same place in the sky. If this is a valid assumption, then the tower is 12 meters tall.
The statue would be eight meters tall. Set up the ratio 40/x = 30/6 Multiple both sides by 6x to get 40*6 = 30x or 240 = 30x Divide both sides by 30 to get 8=x.
Let x = the height of the building. So we have, x/2.6 = 42.25/1.51 x = (2.6)(42.25)/1.51 x =72.75 Thus, the building is 72.75 meter tall.
5.5/8 = x/20 x=5.5*20/8 = 13.75 feet
Let the height of the building be x and use the tangent ratio: x/20 = 6/4 Make x the subject of the equation: x = (6*20)/4 x = 30 ft
It is approx 36.6 ft.
Required angle has a tangent of 7.6/6.1 ie 1.249. This is 51.25 degrees.
28 feet