5.0 molar
To make a 50% solution of 100 ml, you would need to weigh 50g of the active ingredient. This is because in a 50% solution, half of the solution is the active ingredient and half is the solvent.
Let's say the total solution is 100 liters. 50 of the liters is glucose and 50 is water. We want to make the 50 glucose equal to 10% of the total solution. For that to happen, we need to make the total solution 500 liters (50 of the 500 would be a 10% solution). So we add 400 liters of water to the original 100 liter (50/50) solution. Take the total number of units and multiply by 4. Add that much in water.
To make a 500 ml solution of 3% H2O2 from a 50% solution, you would need to dilute the 50% solution with water. You would add 325 ml of water to 175 ml of the 50% H2O2 solution to achieve a final volume of 500 ml with a concentration of 3% H2O2.
To prepare 100 ml of a 5% dextrose solution from a 50% dextrose solution, you would use the formula: C1V1 = C2V2. You will need 10 ml of the 50% solution (C1) and dilute it with 90 ml of water (V1) to obtain the desired 100 ml of 5% dextrose solution.
A 50 ml solution that is 10% acid will consist of 5 ml of acid (10% of the volume) and 45 ml of water (90% of the volume). You're not adding any water, but you want to add enough acid to make a solution that is 50% acid and 50% water. You will need to have a total of 45 ml of acid in the mixture to make it a 50/50 solution, since the amount of water is also 45 ml. You have 5 ml in there already, so you would need to add 40 ml of acid. That would make a total 90 ml solution that is 50% water (45 ml) and 50% acid (45 ml).
The volume reach the half.
50
To make a 10 percent solution, you would need to dilute the 50 percent solution by adding 4 ml of solvent to 1 ml of the 50 percent solution. This will result in a total volume of 5 ml with a 10 percent concentration.
A 38 out of 50 is a 76%. This is calculated by dividing 38 by 50 (38/50). You then multiply the result by 100, and the solution is your percentage out of 100.
To create a 50% chlorinated solution from the 60% and 40% solutions, the chemist will need to mix the two in equal amounts. Therefore, 50 L of the 60% solution and 50 L of the 40% solution are needed to make a 100 L solution that is 50% chlorinated.
If you have a solution that is 50% water and 50% hydrogen peroxide, you would have equal volumes of each component. So if you have 1 liter of this solution, you would have 0.5 liters of water and 0.5 liters of hydrogen peroxide.
To prepare 50 ml of a 1.0 M NaHCO3 solution from a 2.5 M stock solution, she would need to mix 10 ml of the 2.5 M solution with 40 ml of water. This dilution would result in a final concentration of 1.0 M.