5.0 molar
To make a 50% solution of 100 ml, you would need to weigh 50g of the active ingredient. This is because in a 50% solution, half of the solution is the active ingredient and half is the solvent.
To make a 500 ml solution of 3% H2O2 from a 50% solution, you would need to dilute the 50% solution with water. You would add 325 ml of water to 175 ml of the 50% H2O2 solution to achieve a final volume of 500 ml with a concentration of 3% H2O2.
Let's say the total solution is 100 liters. 50 of the liters is glucose and 50 is water. We want to make the 50 glucose equal to 10% of the total solution. For that to happen, we need to make the total solution 500 liters (50 of the 500 would be a 10% solution). So we add 400 liters of water to the original 100 liter (50/50) solution. Take the total number of units and multiply by 4. Add that much in water.
To prepare 100 ml of a 5% dextrose solution from a 50% dextrose solution, you would use the formula: C1V1 = C2V2. You will need 10 ml of the 50% solution (C1) and dilute it with 90 ml of water (V1) to obtain the desired 100 ml of 5% dextrose solution.
A 50 ml solution that is 10% acid will consist of 5 ml of acid (10% of the volume) and 45 ml of water (90% of the volume). You're not adding any water, but you want to add enough acid to make a solution that is 50% acid and 50% water. You will need to have a total of 45 ml of acid in the mixture to make it a 50/50 solution, since the amount of water is also 45 ml. You have 5 ml in there already, so you would need to add 40 ml of acid. That would make a total 90 ml solution that is 50% water (45 ml) and 50% acid (45 ml).
The volume reach the half.
To make a 10 percent solution, you would need to dilute the 50 percent solution by adding 4 ml of solvent to 1 ml of the 50 percent solution. This will result in a total volume of 5 ml with a 10 percent concentration.
50
A 38 out of 50 is a 76%. This is calculated by dividing 38 by 50 (38/50). You then multiply the result by 100, and the solution is your percentage out of 100.
To create a 50% chlorinated solution from the 60% and 40% solutions, the chemist will need to mix the two in equal amounts. Therefore, 50 L of the 60% solution and 50 L of the 40% solution are needed to make a 100 L solution that is 50% chlorinated.
If you have a solution that is 50% water and 50% hydrogen peroxide, you would have equal volumes of each component. So if you have 1 liter of this solution, you would have 0.5 liters of water and 0.5 liters of hydrogen peroxide.
To prepare 50 ml of a 1.0 M NaHCO3 solution from a 2.5 M stock solution, she would need to mix 10 ml of the 2.5 M solution with 40 ml of water. This dilution would result in a final concentration of 1.0 M.