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How would you find x and y intercept in the problem 4x minus 3y minus 12 equals 0?
Wiki User
∙ 12y ago
First put in this form. Y = mX + c
4X - 3Y - 12 = 0
4X - 3Y = - 12
- 3Y = - 4X - 12
Y = (4/3)X + 4
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Points are,
(- 3, 0 ) and ( 0, 4 )
You do not have the full question yet since this question has infinite answers.
4x - 3y - 12 = 0
4x = 3y + 12
If the question only gives this one equation, you can substitute any number into x to get a corresponding answer.
Let's say x = 1
4(1) = 3y - 12
4 = 3y - 12
16 = 3y
y = 5.33 (3 sig fig)
Suppose there is another part to this statement: 4x - 3y - 12 = 0 an 3x = 2y
3x = 2y
x = 2y/3 (choose either of the equations [3x = 2y, since it is easier] and separate either of the letters ["x"] from the other things [other letters and any numbers]
Substitute x = 2y/3 into 4x = 3y + 12
4 (2y/3) = 3y + 12
8y/3 - 3y = 12
-1y/3 = 12
-y = 36
y = -36
Substitute y = -36 into 3x = 2y (easier)
3x = 2(-36)
3x = -72
x = -24
The interception point is (-24,-36). [note that 2 straights lines will either intercept on 1 point (most cases), never (parallel lines with same gradient) or infinite times (same line)]
Wiki User
∙ 12y ago
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