We are told: 16y2 = 120x - 225 The y-intercepts will happen where x equals zero, so we can say: 16y2 = 120(0) - 225 16y2 = -225 y2 = -225 / 16 y = √(-225 / 16) y = ±15i/4
Oh, finding the x and y intercepts is like finding little treasures in your painting. To find the x-intercept, you set y to zero and solve for x. To find the y-intercept, you set x to zero and solve for y. Remember, there are no mistakes in mathematics, just happy little accidents.
If the discriminant is negative, there are 0 interceptsIf the discriminant is zero, there is 1 interceptIf the discriminant is positive, there are 2 intercepts
Zero
Not all equations are equated to zero, but usually we set a function equal to zero if we want to find its x intercepts, or where the graph of the function crosses the x axis.
None because the discriminant of this quadratic equation is less than zero.
Zero
4
The x intercepts are when y=0. Substitute the zero in for all y and then solve. Use quadratic formula and reduce. I got (-1+/- sqrt 10)3 about .72075922 and -1.387425887
An easy way to find the intercepts is to substitue zero into the other variable. y-intercept is when x=0 -2y=27 y=-27/2 y=-13 1/2 is the y-intercept. 9x=27 x=3 is the x-intercept.
Find the x-intercepts of f(x)=(x+4)/x The instructions simply mean that you should set f(x) equal to 0. To get the answer, you must set the numerator equal to zero, so x+4=0. Then x=-4 is the answer.
The y-intercept is the place (or places) where x=0 . So if 'x' is 2y2+3y+1 , then all you have to do is find places where 2y2+3y+1 is zero, and those are your y-intercepts.