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A perpendicular line has the negative reciprocal of the slope. The perpendicular line has a slope of 1/2 y=1/2 + 3 The 3 or y-intercept can really be any number though.
y equals -1/3x plus 4/3
The y intercept would be 3.
Perpendicular would mean that the slope of both lines have to be the same. The slope of the given line is 2, so the equation of the other line is of the form y=2x+c with c some constant. Since it is given that the intercept of the second line is -2, we know that -2 = 0.x + c which gives us c = -2 Using this, we can see that the equation of the perpendicular line is y=2x-2
If the original line has the equation 2y = 7x then this can be written as y = 3.5x and the slope of this line is thus 3.5. Two straight lines are perpendicular if the product of their gradients is -1. Let m be the slope of the perpendicular line then, 3.5m = -1 : m = -1/3.5 = -2/7 The equation of the perpendicular line is thus, y = -2/7 * x + b where b is the intercept. As b = 5 then the equation becomes y = -2/7*x + 5 We can multiply by 7 to eliminate the fraction, 7y = -2x + 35 and re-order the terms to become 7y = 35 - 2x
There is no y-intercept or slope for this given equation, because its graph is a vertical line perpendicular to the x-axis.
A perpendicular line has the negative reciprocal of the slope. The perpendicular line has a slope of 1/2 y=1/2 + 3 The 3 or y-intercept can really be any number though.
y equals -1/3x plus 4/3
If -14 is the y intercept then it is: y = -1/13x -14
The y intercept would be 3.
The equation of a line that is perpendicular to 3y = -x + 9 and that has a y intercept of 6 is y = 3x + 6. The slope of the first line is -1/3, from the slope-intercept form y = mx + b, or y = -x/3 + 3. The perpendicular slope is 3, by negating and inverting -1/3. Add the intercept to the slope-intercept form and you get y = 3x + 6.
It would be perpendicular to a line with the equation Y = 1/8 X.
A line perpendicular to the x-axis does not have a slope nor a y-intercept and so it is not possible to answer the question.
Given a line with slope m, the slope of a perpendicular line is -1/m. So put the equation in slope-intercept form:y = -3x + 4.So slope = -3, and slope of perpendicular line = 1/3. So the new line is: y = mx + b, m = 1/3 and b = 5.y = x/3 + 5
7
Convert the equation 2y = 5x - 4 into standard form then y = 2.5x - 2. Two straight lines are perpendicular if the product of their gradients is -1. Let the equation of the perpendicular line by y = mx + b. Then, 2.5m = -1 : m = -1/2.5 The y intercept occurs when x = 0. Then -3 = 0 + bc : b = -3 The equation of the perpendicular line is y = -1/2.5x -3 or 5y = -2x -15
Slope of given line = 3 So slope of perpendicular = -1/3