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How yo find the formula on how to solve the number of diagonals in a polygon?
Wiki User
∙ 11y ago
It is: 0.5*(n2-3n) = diagonals whereas 'n' is the number of sides of the polygon
Wiki User
∙ 11y ago
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Which polygon has no of sides equal to diagonal?
The formula for the number of diagonals in a polygon is s*(s-1)/2 - s To find such a polygon, we solve for when that formula equals s s*(s-1)/2 - s = s s*(s-1)/2 = 2s (s-1)/2 = 2 s-1 = 4 s = 5 Thus, the polygon with this property is the pentagon.
If the sum of the measures of the interior angles of a polygon is 1980 how many sides does it have?
The formula for the sum of the angles of an interior polygon is 180(n-2), where n is the number of sides, so then you solve 180(n-2) = 1980. (n-2) = 11 n = 13. So the polygon has 13 sides.
If the sum of the measures of the interior angles of a polygon is 1980 degrees how many sides does it have?
The formula for the sum of the angles of an interior polygon is 180(n-2), where n is the number of sides, so then you solve 180(n-2) = 1980. (n-2) = 11 n = 13. So the polygon has 13 sides.
What is the sum of the interior angles of a ten sided polygon?
The formula to solve this is (n-2)*180. Put in ten for n, and you get: (10-2)180. That's 8*180, or 1440. If it is a regular polygon: To get the individual angles, you'd divide by the number of angles there are total: ten, to get 144 degrees per angle.
If the sum of the interior angles of a regular polygon is 1080 degrees how many sides does this polygon have?
Formula to find sum of interior angles (when n = number of sides): 180(n-2) Sub in total and solve for n: 180(n-2) = 1080 180n-360 = 1080 180n = 1080 + 360 180n = 1440 180n/180 = 1440/180 n = 8 Thus, the number of sides is 8 and it is a hexagon.
What is the formula for the sides of a polygon if the diagonals are given?
1/2*(n2-3n) = number of diagonals Rearranging the formula: n2-3n-(2*diagonals) = 0 Solve as a quadratic equation and taking the positive value of n as the number of sides.
WHAT IS THE ANSWER TOD12N(N-3) GIVES THE NUMBER OF DIAGONALS d FOR A POLYGON WITH N SIDES.. use THIS EQUATION TO FIND THE NUMBER OF DIAGONALS FOR POLYGON THAT HAS 13 SIDES .SOLVE?
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How do you find the number of sides of two polygon given the number of diagonals?
Your question is quite confusing because you used the phrase 'two polygon'. When asking mathematical or geometrical questions about shapes you ask about a single specific thing . I assume you meant to ask, '----number of sides of various different polygons, given the number of diagonals in each of them.' I have been drawing polygons with 5 and 6 and 7 and 8 sides and discovering the number of diagonals which can be drawn inside each of them , does not seem to follow a simple formula. I will look into it further and see if I can post you an answer in a day or two. Very interesting question I must say. Hope I can solve it .Additional Information:-The diagonal formula for any polygon is: 1/2*(n2-3n) = number of diagonalsRearrange the formula into a quadratic equation and solve it for a positive value which will be the number of the sides of the given polygon
Which polygon has no of sides equal to diagonal?
The formula for the number of diagonals in a polygon is s*(s-1)/2 - s To find such a polygon, we solve for when that formula equals s s*(s-1)/2 - s = s s*(s-1)/2 = 2s (s-1)/2 = 2 s-1 = 4 s = 5 Thus, the polygon with this property is the pentagon.
What kind of polygon has 54 diagonals?
A polygon with n sides has n*(n-3)/2 diagonals.So you need to solve n*(n-3)/2 = 54n2 - 3n - 108 = 0 which has the solutions n = 12 or n = -9.Since a polygon cannot have a negative number of sides, the answer is 12.A polygon with n sides has n*(n-3)/2 diagonals.So you need to solve n*(n-3)/2 = 54n2 - 3n - 108 = 0 which has the solutions n = 12 or n = -9.Since a polygon cannot have a negative number of sides, the answer is 12.A polygon with n sides has n*(n-3)/2 diagonals.So you need to solve n*(n-3)/2 = 54n2 - 3n - 108 = 0 which has the solutions n = 12 or n = -9.Since a polygon cannot have a negative number of sides, the answer is 12.A polygon with n sides has n*(n-3)/2 diagonals.So you need to solve n*(n-3)/2 = 54n2 - 3n - 108 = 0 which has the solutions n = 12 or n = -9.Since a polygon cannot have a negative number of sides, the answer is 12.
Can a regular polygon have interior angle of 30 degrees?
the formula for the total number of degrees in a polygon is (x=number of sides) (x-2)180=total degree measure and you divide that number by x to get each angle measure of a regular polygon. so ((x-2)180)/x=30 solve for x and you get x=2.4 you can't have 2.4 sides in a polygon. so no, a regular polygon can't have an interior angle of 30 degrees
If the sum of the measures of the interior angles of a polygon is 1980 how many sides does it have?
The formula for the sum of the angles of an interior polygon is 180(n-2), where n is the number of sides, so then you solve 180(n-2) = 1980. (n-2) = 11 n = 13. So the polygon has 13 sides.
How do you solve regular and irregular polygons?
The answer depends on what you mean by "solve" a polygon. Do you want to find the number of sides or vertices, or lengths of sides, or measures of angles, or their sum, or the area of the polygon or its perimeter? And the answer, in most cases, will depend on what information you do have.The answer depends on what you mean by "solve" a polygon. Do you want to find the number of sides or vertices, or lengths of sides, or measures of angles, or their sum, or the area of the polygon or its perimeter? And the answer, in most cases, will depend on what information you do have.The answer depends on what you mean by "solve" a polygon. Do you want to find the number of sides or vertices, or lengths of sides, or measures of angles, or their sum, or the area of the polygon or its perimeter? And the answer, in most cases, will depend on what information you do have.The answer depends on what you mean by "solve" a polygon. Do you want to find the number of sides or vertices, or lengths of sides, or measures of angles, or their sum, or the area of the polygon or its perimeter? And the answer, in most cases, will depend on what information you do have.
How do you solve a magic square?
all verticals, horazontals and diagonals must add up to one common number
How many sides does a regular polygon have when it has 54 diagonals?
Suppose the polygon has n sides. Then n*(n-3)/2 = 54 or n*(n-3) = 108 and so, by inspection, n = 12 or you can multiply out the brackets and solve the quadratic equation in n.
If the sum of the measures of the interior angles of a polygon is 1980 degrees how many sides does it have?
The formula for the sum of the angles of an interior polygon is 180(n-2), where n is the number of sides, so then you solve 180(n-2) = 1980. (n-2) = 11 n = 13. So the polygon has 13 sides.
How do you solve a convex polygon?
You cannot solve a convex polygon! You can solve some questions regarding its angles, or side lengths or area or perimeter. But a convex polygon, in itself, is not something that can be solved!
