To find AC, you need to add the lengths of segments BC and CD together. If BC is 7 and CD is 24, then AC = BC + CD = 7 + 24 = 31. Therefore, AC is 31 units long.
To construct quadrilateral ABCD with specified lengths for sides AB, BC, CD, and diagonals AC and BD, start by drawing triangle ABC with the given lengths for sides AB and BC. Use the length of AC to find point C, ensuring that it connects to the endpoint of BC. From point A, draw line segment AD such that it matches the length of AD, then connect point C to point D to complete the quadrilateral, ensuring that the length CD is also as specified. Make sure to use a compass and straightedge for accurate measurements.
If BC = 10.4and CD = 14.4, what is BD?
Yes, the expression AC + AD + BC + BD can be factored as (A + C)(B + D). This is evident by applying the distributive property, where expanding (A + C)(B + D) yields AB + AD + BC + CD. The terms AC and BD are not present, so the expression can be expressed in a different form, but the original expression itself represents a different factoring structure.
ABCD is a squre. forces of magnitudes 1,2,3,P, and Q units act along AB, BC, CD, DA and AC respectively. find the value of P and Q so that the resultant of five forces is a couple
The diagonals arenotthe sides. They're lines you draw from one angle of the parallelogram to the angle opposite it. So if you have parallelogram ABCD, your diagonals are AC and BD, because AB, BC, CD, and DA are all sides.
If BC=4.5,CD=,7.7,and AD=16.7. Find AB to the nearest tenth If BC=4.5,CD=,7.7,and AD=16.7. Find AB to the nearest tenth
First of all we work out the length of a sides ab, bc, CD, & ad. We know that ab = bc = CD = ad also ae = ac/2 If a to e = 2 then ac = 4 so ab2 + bc2 = ac2 2ab2 = 16 ab2 = 8 ab = 2.8284271247461900976033774484194 so the perimeter = ab * 4 = 11.31
You can find the Authentication key on the Front of your WoW , BC ,WOTLK Cd-case.
If BC = 10.4and CD = 14.4, what is BD?
the song T.N.T by ac/dc is found on the CD called HIGH VOLTAGE
It is easiest to draw it using two right angled triangles.Draw a line AB that is 2 units long. From B, draw BC which is perpendicular to AB and 2 units long. Join AC. From C, draw CD which is perpendicular to AC (clockwise if BC is clockwise from AB, or anticlockwise if BC is anticlockwise) and make CD 2 uinits long. Then AD is a line segment which is sqrt(12) units long.
No, four lines can can have 6 total intersections. They would be Ab, Ac, Ad, Bc, Bd, and Cd
Six. If the sides are labelled a, b, c and d then the congruent pairs are: ab, ac, ad, bc, bd and cd
im pretty sure it depends on the type of reaction wether its a synthesis (a+B=ab), single displacment (a+bc=b+ac) or double displacment(ab+cd=ad+bc).
Yes, the expression AC + AD + BC + BD can be factored as (A + C)(B + D). This is evident by applying the distributive property, where expanding (A + C)(B + D) yields AB + AD + BC + CD. The terms AC and BD are not present, so the expression can be expressed in a different form, but the original expression itself represents a different factoring structure.
You cannot prove it since it is not true for a general quadrilateral.
EC = 9 in. CD = in. Find ED