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Q: If P equals 2L - 2W solve for L if P equals 40 and W equals 2?
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If you know both the perimeter an the length of a rectangle how can you determine the width of the rectangle?

The perimeter is the total of all 4 sides of the rectangle, and a rectangle, by definition, has 2 sets of parallel sides. Perimeter = 2L + 2W (where L = length of ONE side, and W = width of ONE side). So, for example, if the perimeter is 40 cm, and the length is 15 cm, you figure out the width by subtraction and division. P = 2L + 2W 40 = 2(15) + 2W 40 = 30 + 2W 40-30 =30 + 2W - 30 10 = 2W 10/2 = 2W/2 5 = W So the width of the rectangle is 5 cm.


What is the area if perimeter is 96 and l equals 5w?

Assuming this question is asking about a rectangle: Perimeter = 2l + 2w and according to this problem Perimeter = 96, so 96 = 2l + 2w If l = 5w, then we can replace each l in the statement above with 5w, so 96 = 2(5w) + 2w 96 = 10w + 2w 96 = 12w 8 = w If 8 = w, and l = 5w, then l = 5 times 8 = 40 The area of a rectangle is length (l) times width (w), so A = lw A = (40) (8) A = 320 square units


The perimeter of a rectangular playing field is 244 feet If its length is 2 feet longer than twice its width what are the dimensions of the field?

The answer is W=40 and L=82 If you're wondering how to solve it, then let "P" represent perimeter "L" represent length and "W" represent width. P=2L+2W L=2W+2 244=2(2W+2)+2W 244=4W+4+2W 244=6W+4 6W=244 244/6W= W=40 Now plug the 40 in for w in: L=2W+2 L=2(40)+2 L=80+2 L=82 final answer: L=82 and W=40


What is the perimeter of a garden 20 ft long and 15 ft wide?

2L + 2W 2*20=40 2*15=30 40+30= 70 ft


What is the length and width of a rectangular garden that's perimeter is 40 feet and the width is 2 more than one half the length?

2L+2W=40, W=2+L/2, so 2L+4+L=40, 3L=36, L=12, W=8.


What is the dimensions of rectangle room is 8ft longer than twice the width the perimeter is 136?

P = 2l + 2wl = 2w + 8P = 136136 = 2l + 2w136 = 2(2w+8) + 2w136 = 4w + 16 + 2w136 = 6w + 16120 = 6ww = 20l = 2(20) + 8l = 40 + 8l = 48CHECK:136 = 2l + 2w136 = 2(48) + 2(20)136 = 96 + 40136 = 136


The perimeter of a rectangle is 40 centimeters and the area is 64 centimeters 2?

The rectangle has Length = 16 cm and Width = 4 cm.Perimeter = 2L + 2W = 2(16) + 2(4) = 32 + 8 = 40 cmArea = L W = 16 x 4 = 64 cm2


20h-40 equals 8h plus 152?

How do you solve this equation 20h-40=8h+152 ?


Solve the proportion 3 over 8 equals x over 40?

Is it 15 over 40?


What is w and l in lw equals 2800 and 2l plus 2w equals 220?

l + w = 110 so l = 110 - w, making lw = 110w - w2 which equals 2800. This rearranges to w2 - 110w + 2800 = 0. The factors of this are (w - 70)(w - 40) so w = 40 and l = 70. Factors of 2800 are 2 x 1400, 4 x 700, 5 x 560, 7 x 400, 8 x 350, 10 x 280, 20 x 140, 25 x 112, 70 x 40


How wide is a rectangle 12 inches long with a perimeter of 40 inches?

a rectangle has 4 sides and 2 are the length and are the same length and 2 are the width and are also both the same. perimeter is the measurement off adding up all the side on a rectangle. you know the length is 12 inches so you multiple it by 2 since there are two lengths that are the same size take 40 - 24 = 16inches now since there are 2 widths you divide 16 by 2 so the width of your rectangle is 8 inchesUtiilize Algebra: Here is the Solution;P= Perimeter, L = Length, and W = WidthP = 2L+2W(2*12) + (2w) = 40(24) + (2w) = 402w = (40 - 24)2w = 16w = 2/16w = 8


EO equals 2X minus 20 and OC equals 70 minus X solve for X?

40