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Q: If P equals 2L - 2W solve for L if P equals 40 and W equals 2?
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What is the dimensions of rectangle room is 8ft longer than twice the width the perimeter is 136?

P = 2l + 2wl = 2w + 8P = 136136 = 2l + 2w136 = 2(2w+8) + 2w136 = 4w + 16 + 2w136 = 6w + 16120 = 6ww = 20l = 2(20) + 8l = 40 + 8l = 48CHECK:136 = 2l + 2w136 = 2(48) + 2(20)136 = 96 + 40136 = 136


If you know both the perimeter an the length of a rectangle how can you determine the width of the rectangle?

The perimeter is the total of all 4 sides of the rectangle, and a rectangle, by definition, has 2 sets of parallel sides. Perimeter = 2L + 2W (where L = length of ONE side, and W = width of ONE side). So, for example, if the perimeter is 40 cm, and the length is 15 cm, you figure out the width by subtraction and division. P = 2L + 2W 40 = 2(15) + 2W 40 = 30 + 2W 40-30 =30 + 2W - 30 10 = 2W 10/2 = 2W/2 5 = W So the width of the rectangle is 5 cm.


What is the length and width of a rectangular garden that's perimeter is 40 feet and the width is 2 more than one half the length?

2L+2W=40, W=2+L/2, so 2L+4+L=40, 3L=36, L=12, W=8.


The perimeter of a rectangular playing field is 244 feet If its length is 2 feet longer than twice its width what are the dimensions of the field?

The answer is W=40 and L=82 If you're wondering how to solve it, then let "P" represent perimeter "L" represent length and "W" represent width. P=2L+2W L=2W+2 244=2(2W+2)+2W 244=4W+4+2W 244=6W+4 6W=244 244/6W= W=40 Now plug the 40 in for w in: L=2W+2 L=2(40)+2 L=80+2 L=82 final answer: L=82 and W=40


What is the area if perimeter is 96 and l equals 5w?

Assuming this question is asking about a rectangle: Perimeter = 2l + 2w and according to this problem Perimeter = 96, so 96 = 2l + 2w If l = 5w, then we can replace each l in the statement above with 5w, so 96 = 2(5w) + 2w 96 = 10w + 2w 96 = 12w 8 = w If 8 = w, and l = 5w, then l = 5 times 8 = 40 The area of a rectangle is length (l) times width (w), so A = lw A = (40) (8) A = 320 square units


The length of a rectangle is 4 inches less than 2 times the width If the perimeter is 40 inches what are the dimensions?

width=8 length=122w-4=l2w+2l=402w+2(2w-4)=402w+4w-8=406w=48w=82(8)-4=l16-4=l12=l


What is the perimeter of a garden 20 ft long and 15 ft wide?

2L + 2W 2*20=40 2*15=30 40+30= 70 ft


The length of a rectangle is 12ft longer than twice the width if the perimeter is 108 ft What is the length and the width?

L = 12 + 2WL + W = 54(12 + 2W) + W = 5412 + 3W = 543W = 42W = 14L = (12 + 2W) = 40Perimeter = 2L + 2W = 28 + 80 = 108


What is w and l in lw equals 2800 and 2l plus 2w equals 220?

l + w = 110 so l = 110 - w, making lw = 110w - w2 which equals 2800. This rearranges to w2 - 110w + 2800 = 0. The factors of this are (w - 70)(w - 40) so w = 40 and l = 70. Factors of 2800 are 2 x 1400, 4 x 700, 5 x 560, 7 x 400, 8 x 350, 10 x 280, 20 x 140, 25 x 112, 70 x 40


How wide is a rectangle 12 inches long with a perimeter of 40 inches?

a rectangle has 4 sides and 2 are the length and are the same length and 2 are the width and are also both the same. perimeter is the measurement off adding up all the side on a rectangle. you know the length is 12 inches so you multiple it by 2 since there are two lengths that are the same size take 40 - 24 = 16inches now since there are 2 widths you divide 16 by 2 so the width of your rectangle is 8 inchesUtiilize Algebra: Here is the Solution;P= Perimeter, L = Length, and W = WidthP = 2L+2W(2*12) + (2w) = 40(24) + (2w) = 402w = (40 - 24)2w = 16w = 2/16w = 8


Solve the proportion 3 over 8 equals x over 40?

Is it 15 over 40?


20h-40 equals 8h plus 152?

How do you solve this equation 20h-40=8h+152 ?


What is the answer to -40 equals -5p?

-35


EO equals 2X minus 20 and OC equals 70 minus X solve for X?

40


You write 4x plus 4y equals 40?

How do you write 4x plus 4y equals 40 or how do you solve it? You would write it 4x+4y=40 you would solve it for y by subtracting 4x from both sides 4y=40-4x then divide all of that by 4y=40-4x/4 that's if you were graphing i have no idea what you're asking hope that helps if it's not too late.


Solve the following 32 divided by 4 plus 4 x 8 equals?

The final answer is 40.


Solve this equation -9-6 plus 12h plus 40 equals 22?

h= -4


Solve this equation 9h-6 plus 12h plus 40 equals 22?

h=8


How do you solve 40-7x equals -16?

40 -7x = -16 -7x = -16 -40 -7x = -56 x = 8


If the perimeter of a rectangular swimming pool is 320 feet and the length is three times the width what is the dimensions?

Dimensions are 120x40 ExplanationLet L be the length and W be the width. L=3WAnd 2L+2W=320So6W+2W=3208W=320W=40and L=120


Solve by the method of elimination 2x plus 3y equals 40 3x plus 2y equals 20?

y=16 x= -4


What is the answer to this problem -40 equals b over 5?

To solve, think of it as something (b) over 5 is -40, which means that something divided by 5 is -40, so that something must be 5 times -40 or -200.


How do you solve 40 equals 4-6x?

40=4-6x 40-(4)=4-6x-(4) 36=-6x -6=x


What is the length of a rectangle if the perimeter is 100ft and the width is 20ft?

The perimeter of a rectangle is the sum of all of the sides. That is, length + width + length + width, or 2*length + 2*width. So the total width of the two widths is 20 + 20 = 40ft. By subtracting the total width from the perimeter, we can find the total length. 100 - 40 = 60ft. Because there are two lengths in a rectangle, to find one we must divide by two. 60/2 = 30ft. The length is 30 ft. This problem can also be done algebraically. As an algebraic equation, 2L + 2W = P We know W = 20 and P = 100. 2L + 2*[20] = [100] By multiplication, 2L + 40 = 100 By subtraction, 2L = 100 - 40. 2L = 60 By division, L = 60/2 L = 30ft


Solve this equation -9h - 6 plus 12h plus 40 equals 22?

The solution to this equation is that h is equal to -4. You can substitute this value for h into the equation to get -4 x -9 - 6 plus 12 x -4 plus 40 equals 22, or 36 - 6 plus - 48 plus 40 equals 22.