22
The perimeter is the total of all 4 sides of the rectangle, and a rectangle, by definition, has 2 sets of parallel sides. Perimeter = 2L + 2W (where L = length of ONE side, and W = width of ONE side). So, for example, if the perimeter is 40 cm, and the length is 15 cm, you figure out the width by subtraction and division. P = 2L + 2W 40 = 2(15) + 2W 40 = 30 + 2W 40-30 =30 + 2W - 30 10 = 2W 10/2 = 2W/2 5 = W So the width of the rectangle is 5 cm.
40=4-6x 40-(4)=4-6x-(4) 36=-6x -6=x
The final answer is 40.
-9h-6+12h+40=22 -9h+12h=22-40+6 3h=-12 h=-4
2a + 2b = 160 But b = a + 40 so 2a + 2(a + 40) = 160 ie 2a + 2a + 80 = 160 or 4a = 80 ie a = 20 Then b = a + 40 gives b = 20 + 40 = 60 Solution: a = 20, b = 60
The perimeter is the total of all 4 sides of the rectangle, and a rectangle, by definition, has 2 sets of parallel sides. Perimeter = 2L + 2W (where L = length of ONE side, and W = width of ONE side). So, for example, if the perimeter is 40 cm, and the length is 15 cm, you figure out the width by subtraction and division. P = 2L + 2W 40 = 2(15) + 2W 40 = 30 + 2W 40-30 =30 + 2W - 30 10 = 2W 10/2 = 2W/2 5 = W So the width of the rectangle is 5 cm.
Assuming this question is asking about a rectangle: Perimeter = 2l + 2w and according to this problem Perimeter = 96, so 96 = 2l + 2w If l = 5w, then we can replace each l in the statement above with 5w, so 96 = 2(5w) + 2w 96 = 10w + 2w 96 = 12w 8 = w If 8 = w, and l = 5w, then l = 5 times 8 = 40 The area of a rectangle is length (l) times width (w), so A = lw A = (40) (8) A = 320 square units
The answer is W=40 and L=82 If you're wondering how to solve it, then let "P" represent perimeter "L" represent length and "W" represent width. P=2L+2W L=2W+2 244=2(2W+2)+2W 244=4W+4+2W 244=6W+4 6W=244 244/6W= W=40 Now plug the 40 in for w in: L=2W+2 L=2(40)+2 L=80+2 L=82 final answer: L=82 and W=40
2L + 2W 2*20=40 2*15=30 40+30= 70 ft
2L+2W=40, W=2+L/2, so 2L+4+L=40, 3L=36, L=12, W=8.
P = 2l + 2wl = 2w + 8P = 136136 = 2l + 2w136 = 2(2w+8) + 2w136 = 4w + 16 + 2w136 = 6w + 16120 = 6ww = 20l = 2(20) + 8l = 40 + 8l = 48CHECK:136 = 2l + 2w136 = 2(48) + 2(20)136 = 96 + 40136 = 136
The rectangle has Length = 16 cm and Width = 4 cm.Perimeter = 2L + 2W = 2(16) + 2(4) = 32 + 8 = 40 cmArea = L W = 16 x 4 = 64 cm2
How do you solve this equation 20h-40=8h+152 ?
Is it 15 over 40?
l + w = 110 so l = 110 - w, making lw = 110w - w2 which equals 2800. This rearranges to w2 - 110w + 2800 = 0. The factors of this are (w - 70)(w - 40) so w = 40 and l = 70. Factors of 2800 are 2 x 1400, 4 x 700, 5 x 560, 7 x 400, 8 x 350, 10 x 280, 20 x 140, 25 x 112, 70 x 40
a rectangle has 4 sides and 2 are the length and are the same length and 2 are the width and are also both the same. perimeter is the measurement off adding up all the side on a rectangle. you know the length is 12 inches so you multiple it by 2 since there are two lengths that are the same size take 40 - 24 = 16inches now since there are 2 widths you divide 16 by 2 so the width of your rectangle is 8 inchesUtiilize Algebra: Here is the Solution;P= Perimeter, L = Length, and W = WidthP = 2L+2W(2*12) + (2w) = 40(24) + (2w) = 402w = (40 - 24)2w = 16w = 2/16w = 8
40