There are 16 possible outcomes (2*2*2*2) of which two - all heads or all tails - satisfy the requirements. So the probability is 2/16 = 1/8 = 12.5%
1 chance in 4
6/16 = 3/8
Each one is 50% Together it's 25% (.5 x .5 = .25)
1/16 These are four independent events each with a 1/2 probability. The probability that all four occur (penny and nickels heads and dime and quarter tails) is: 1/2*1/2*1/2*1/2=(1/2)4=1/16.
The probability of getting a 2 on a six sided die is 1/6. The probability of rolling a 5 is 1/6 The probability that any of the six numbers will come up is 1/6. Probability is found by "the number of ways of getting the favorable event/the total number of possibilities". Since there is only one number 2 on a a die, then there is only one way to get the favorable event. The total number of sides on a die is 6, so there are six different possibilities total that can come up. So, probability of rolling a 2 is 1/6.
The probability of 10 heads in a row is (0.5)10 = 0.000977 = 0.0977% .It makes no difference what has come before or what comes after.
If two six sided fair dice are rolled, the sum of the result of both dice that has the lowest probability to come up is 2 and 12. P(2) = 1/36. P(12) = 1/36.
Three coins can come up in (2 x 2 x 2) = 8 different ways.One tail can come up in 3 different ways . . . one for each coin.The probability of one tail is (3/8) = 0.375 = 37.5%
If you roll a fair six-sided die 1000 times the die would come up even about 500 times. It will not be exactly 500 times, due to random probability, but it will be close. The more times you roll it, the ratio of even to odd will come closer and closer to the theoretical probability of 0.5.
11 ways (out of 36, resulting in a probability of 11/36):1-3, 2-3, 3-3, 4-3, 5-3, 6-3, 3-1, 3-2, 3-4, 3-5, 3-6
50%.
We assume a 6 sided fair die. Now, note that the probability of rolling any number is independent of the probability of the outcome on the next role of the die. In probability terms we say the two events are independent this implies that is we look at the probability of A and the probability of B the probability of A and B is P(A)xP(B) Since we are look at the probability of a 5 and there are 6 possible outcomes, the probability of a 5 is 1/6 and a similar argument tells us the probability of a 2 is 1/6. Now, since they are independent, the probability of a 5 AND a 2 is 1/6 x 1/6=1/36 If you want to consider dice with different shapes and fewer than 6 numbers, the answer will change. I have considered only a 6 sided fair die since if one understands how this works, one can generalize to other scenarios. The commonly used die is called a cubic polyhedron. Dice come as many different polyhedra and these make for interesting probability questions.