11 ways (out of 36, resulting in a probability of 11/36):1-3, 2-3, 3-3, 4-3, 5-3, 6-3, 3-1, 3-2, 3-4, 3-5, 3-6
There are 11 ways.
If they are fair dice, the probability is 0.0032If they are fair dice, the probability is 0.0032If they are fair dice, the probability is 0.0032If they are fair dice, the probability is 0.0032
The probability is 90/216 = 5/12
These are independent one has no bearing on the other
5/36 or 13.9%.
It is 11/36.It is 11/36.It is 11/36.It is 11/36.
If they are fair dice, the probability is 0.0032If they are fair dice, the probability is 0.0032If they are fair dice, the probability is 0.0032If they are fair dice, the probability is 0.0032
The probability is 90/216 = 5/12
There are 72 permutations of two dice and one coin.
These are independent one has no bearing on the other
5/36 or 13.9%.
It is 11/36.It is 11/36.It is 11/36.It is 11/36.
It is (5/6)2 = 25/36
The answer depends on the experiment: how many coins are tossed, how often, how many dice are rolled, how often.
It could be dice (craps) : 7 for a "seven natural" to be thrown (more rarely tossed)
There are 6 outcomes, a 2 is one of them so the probability is 1/6.
Assuming you're talking about standard six-sided dice numbered 1-6, the least likely rolls are 2 and 12, each of which should come up 1 time in every 36 rolls on average.
Yes, quite easily.