To determine how long it takes for the cricket to land back on the ground after jumping with an initial vertical velocity of 4 ft per second, we can use the formula for the time of flight in projectile motion. The time to reach the maximum height is given by ( t = \frac{v}{g} ), where ( v ) is the initial velocity and ( g ) is the acceleration due to gravity (approximately 32 ft/s²). In this case, it takes ( t = \frac{4}{32} = 0.125 ) seconds to reach the peak. Since the time to ascend and descend is equal, the total time until the cricket lands back on the ground is ( 2 \times 0.125 = 0.25 ) seconds.
4ft*Ns=H
Acceleration of the arrow is -3m/s2A = (velocity minus initial velocity) / time
it means initial upwards height times time in seconds
the answer is 24-9 m/sec. yuor welcome
Acceleration = Change in Velocity / Change in Time a = (Final Velocity - Initial Velocity) / (Final Time - Initial Time) = (55-0)/(5-0) = 55/5 a = 11 m/s^2
4ft*Ns=H
To calculate acceleration, you need to know the initial velocity of the car and its final velocity after 6.8 seconds. The acceleration can be found using the formula: acceleration = (final velocity - initial velocity) / time.
That depends on its initial velocity and its acceleration. V1 = V0 + a * t
The stone will return to the ground when its vertical velocity becomes zero and it starts to fall back down. The time it takes for this to happen can be calculated using kinematic equations. In this case, the time can be found by setting the vertical velocity to zero and solving for time.
Acceleration of the arrow is -3m/s2A = (velocity minus initial velocity) / time
The acceleration of the car can be calculated using the formula: acceleration = (final velocity - initial velocity) / time. In this case, the final velocity is 20+10 = 30 miles/sec, the initial velocity is 20 miles/sec, and the time is 30 seconds. So, the acceleration of the car is (30 - 20) / 30 = 0.33 miles/sec^2.
Acceleration occurs when velocity changes over time. The formula for it is as follows: a = (Vf - Vi) / t a: acceleration (meters/seconds2) Vf: Final velocity (meters/seconds) Vi: Initial Velocity (meters/seconds) t: Time (seconds)
To calculate the braking time from 1.5 to 2 seconds, we need to know the initial velocity and the acceleration of the object. The final velocity can be determined using the formula: final velocity = initial velocity + (acceleration * time). If we have this information, we can plug in the values to find the final velocity at 2 seconds.
l2Math. l2Math.
it means initial upwards height times time in seconds
The train's velocity after 30 seconds can be calculated using the formula: final velocity = initial velocity + (acceleration * time). Plugging in the values, final velocity = 20 km/hr + (4 km/hr/s * 30 s) = 20 km/hr + 120 km/hr = 140 km/hr. So, the train's velocity after 30 seconds is 140 km/hr.
The acceleration of the car can be calculated using the formula: acceleration = (final velocity - initial velocity) / time. Given the initial velocity (A), final velocity (B), and time (8 seconds), you can substitute the values into the formula to find the acceleration.