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If a game there are two fair number cubes that are rolled To make the first move you need to roll a total of 6 or 7 or 8 What is the probability that you will be able to make the first move?
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∙ 15y ago
Three out of twelve
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∙ 15y ago
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A six sided die is rolled twice what is the probability of rolling either an even number on the first roll or a 1 on the second roll the answer is 7 over 12 but I can't figure out how to get there?
The question asks "What is the probability of rolling either an even number on the first roll or a 1 on the second roll?" These events are independent from each other as the outcome of the second roll is not affected by the outcome of the first roll. However, these events are non-mutually exclusive, meaning that these events can both occur at the same time.The probability of rolling an even number on the first roll is 3/6 because 2, 4, and 6 are even numbers and a six-sided die has six possible numbers.The probability of rolling a 1 on the second roll is 1/6.If these two probabilities are added together, we will have "double counted" the event where an even number is rolled on the first roll and a 1 is rolled on the second roll. To correct for this, we must subtract the probability of both events occurring.The probability that both events occur is 3/36, because 3/6 * 1/6 = 3/36.Now, the probability of rolling either an even number on the first roll or a 1 on the second roll is:3/6 + 1/6 - 3/36= 18/36 + 6/36 - 3/36= 21/36= 7/12
What is the probability of a square number?
In the set of the first n integers, the number of a square number is approximately sqrt(n). So the probability of a square number is sqrt(n)/n = 1/sqrt(n). As n becomes larger this probability tends towards 0.
What are the chances of rolling the number seven with two dice?
There are 36 permutations of two dice. Of these, six have a sum of seven. The probability, then, of rolling a seven on two dice is 6 in 36, or 1 in 6, or about 0.1667.It does not matter if two dice are rolled one time, or if one die is rolled two times. The probability of rolling a sum of 7 is still about 0.1667.The first thing to do is to identify all possible combinations which could give the sum of 7. These are: 6 and 1, 5 and 2, 4 and 3, 3 and 4, 2 and 5, and 1 and 6.Thus there are 6 possible combinations.For each of these combinations, the probability of getting the 1st number correct is 1/6 and the probability of getting the second number correct is 1/6, and so the overall probability of the combination is 1/36There are 6 ways to get 7 though so 6x 1/36 = 1/6Which means the probability that 2 dice rolls will add up to 7 is 1/6
If 5 distinct dice are rolled what is the probability of getting at least one 6?
You must notice that it is easier to find the probability that none of the dice are six. This is the complement of the answer. Pc= (55)/(65) = .4019 *the first die has 5 ways to not equal six, and so on for the remaining dice. [55] outcomes have no six. *the total number of outcomes gives each die 6 ways to fall. [65] outcomes overall. *Probability is the favorable outcome divided by the total number of outcomes. *Probability of an event is 1 minus the complement of the event. P = 1 - .4019 P = .5981 <<<<<<FINAL ANSWER
Two dice are rolled what is the probability of rolling at least one six?
First calculate the probability of not rolling a six - since there are 5 possibilities for each die, this is (5/6) x (5/6). Then calculate the complement (1 minus the probability calculated).First calculate the probability of not rolling a six - since there are 5 possibilities for each die, this is (5/6) x (5/6). Then calculate the complement (1 minus the probability calculated).First calculate the probability of not rolling a six - since there are 5 possibilities for each die, this is (5/6) x (5/6). Then calculate the complement (1 minus the probability calculated).First calculate the probability of not rolling a six - since there are 5 possibilities for each die, this is (5/6) x (5/6). Then calculate the complement (1 minus the probability calculated).
What is the probability of rolling the same number when three number cubes are rolled?
The first roll doesn't matter for probability, it just sets the number to be rolled by the other two. So: P(rolling the same number three times) = P(rolling a particular number)2 = (1/6)2 = 1/36
Two number cubes are rolled what is probubility of 1 and 2?
First of all it is probability second of all the answer is 1/6+1/6 which is 2/12 which simplified is 1/6
What is the probability of rolling 3 number cubes and having the first land on 2 and the second land on 3 and the third land on 4?
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What is the probability of rolling 2 number cubes and having the first land on an odd number and the second land on 1'?
(1/2) * (1/6) = 1/12
You roll two number cubes what is the probability that you roll a 1 first and a 2 second?
Since there are 6 sides on every die that are equally likely to be rolled, the probability of rolling any given side once is exactly 1/6. The 2 events or the first and second dice roll are independent (the outcome of one does not influence the other) so to find the probability of both occurring you just multiply the probability of each event. Since each event has a 1/6 probability of occurring as stated before, The entire event has a probability of 1/6*1/6 or 1/36, which is approximately 2.78%.
If You roll a fair number cube twice What is the probability of rolling two threes if the first roll is a 5?
2/36 what you rolled the first time has nothing to do with the next roll. It's an independent event.
There are 12 green cubes and 18 yellow cubes in a bag What is the probability in simplest form that a yellow cube will be chosen on the first draw?
3/5 or three fifths.
What is the first number in a probability ratio?
The number of "favourable" outcomes.
A six sided die is rolled twice what is the probability of rolling either an even number on the first roll or a 1 on the second roll the answer is 7 over 12 but I can't figure out how to get there?
The question asks "What is the probability of rolling either an even number on the first roll or a 1 on the second roll?" These events are independent from each other as the outcome of the second roll is not affected by the outcome of the first roll. However, these events are non-mutually exclusive, meaning that these events can both occur at the same time.The probability of rolling an even number on the first roll is 3/6 because 2, 4, and 6 are even numbers and a six-sided die has six possible numbers.The probability of rolling a 1 on the second roll is 1/6.If these two probabilities are added together, we will have "double counted" the event where an even number is rolled on the first roll and a 1 is rolled on the second roll. To correct for this, we must subtract the probability of both events occurring.The probability that both events occur is 3/36, because 3/6 * 1/6 = 3/36.Now, the probability of rolling either an even number on the first roll or a 1 on the second roll is:3/6 + 1/6 - 3/36= 18/36 + 6/36 - 3/36= 21/36= 7/12
What is the probability of rolling a 2 and then a 3 with 6-sised cubes?
The probability of rolling a 2 on the first roll is 1 in 6. The probability of rolling a 3 on the second roll is 1 in 6. However, the probability of rolling a 2 on the first roll and 3 on the second roll before you roll at all is 1/6 x 1/6 = 1 in 36.
What is the probality of rolling a sum of 5 or 6 when rolling two cubes?
-- The first cube can show any one of 6 numbers. For each of those, the second cube can also show any one of 6 numbers. So there are (6 x 6) = 36 ways the two cubes can fall. -- 5 can be rolled in any of these ways: 1-4, 2-3, 3-2, 4-1 = 4 ways -- 6 can be rolled in any of these ways: 1-5, 2-4, 3-3, 4-2, 5-1 = 5 ways -- The roll can be either 5 or 6 in (4 + 5) = 9 ways. -- Probability = (number of successes) / (number of possibilities) = (9 / 36) = 1/4 = 25 %
You rolled doubles with a pair of dice what is the probability that the total is less than 9?
You have rolled doubles so the full set of possible outcomes is [1,1], [2,2], [3,3], [4,4],[5,5] and [6,6] - that is six in all. Of these the first four are favourable outcomes (sum < 9) So the required probability is 4/6 or 2/3
