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Since there are 6 sides on every die that are equally likely to be rolled, the probability of rolling any given side once is exactly 1/6. The 2 events or the first and second dice roll are independent (the outcome of one does not influence the other) so to find the probability of both occurring you just multiply the probability of each event. Since each event has a 1/6 probability of occurring as stated before, The entire event has a probability of 1/6*1/6 or 1/36, which is approximately 2.78%.

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Q: You roll two number cubes what is the probability that you roll a 1 first and a 2 second?
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Related questions

What is the probability of rolling 3 number cubes and having the first land on 2 and the second land on 3 and the third land on 4?

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What is the probability of rolling 2 number cubes and having the first land on an odd number and the second land on 1'?

(1/2) * (1/6) = 1/12


Two number cubes are rolled what is probubility of 1 and 2?

First of all it is probability second of all the answer is 1/6+1/6 which is 2/12 which simplified is 1/6


What is the probability of rolling a 2 and then a 3 with 6-sised cubes?

The probability of rolling a 2 on the first roll is 1 in 6. The probability of rolling a 3 on the second roll is 1 in 6. However, the probability of rolling a 2 on the first roll and 3 on the second roll before you roll at all is 1/6 x 1/6 = 1 in 36.


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None, because you cannot have the first or second dice: it is the first die or second die. The probability is 1/6 * 1/2 = 1/12


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Count the total number of ways it can turn out. Count the number of ways that are the condition you're looking for. The probability of the outcome you're looking for is is the second number divided by the first number.


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