Since there are 6 sides on every die that are equally likely to be rolled, the probability of rolling any given side once is exactly 1/6. The 2 events or the first and second dice roll are independent (the outcome of one does not influence the other) so to find the probability of both occurring you just multiply the probability of each event. Since each event has a 1/6 probability of occurring as stated before, The entire event has a probability of 1/6*1/6 or 1/36, which is approximately 2.78%.
First of all it is probability second of all the answer is 1/6+1/6 which is 2/12 which simplified is 1/6
The first roll doesn't matter for probability, it just sets the number to be rolled by the other two. So: P(rolling the same number three times) = P(rolling a particular number)2 = (1/6)2 = 1/36
The first dice can show any number. However the second dice has a 1 in 6 chance of being the same as the first. Hence the probability of getting two numbers the same is 1/6.
Of all the six numbers on a cube, only the '5' is not a factor of 12.Probability of rolling a factor of 12 on the first cube = 5/6 .Probability of rolling a factor of 12 on the second cube = 5/6 .Probability of rolling a factor of 12 on both cubes = (5/6 x 5/6 ) = 25/36 = 694/9 %.
Assuming that a dice roll is purely random, there is a 1 in 6 probability of landing on any number. Since the second roll depends on the probability of the first, they factor together: First Roll: 1/6 Second Roll: (1/6)(1/6) = 1/36 If you were rolling both dice at once, however, the math would be completely different.
triangle
(1/2) * (1/6) = 1/12
First of all it is probability second of all the answer is 1/6+1/6 which is 2/12 which simplified is 1/6
The probability of rolling a 2 on the first roll is 1 in 6. The probability of rolling a 3 on the second roll is 1 in 6. However, the probability of rolling a 2 on the first roll and 3 on the second roll before you roll at all is 1/6 x 1/6 = 1 in 36.
25%
None, because you cannot have the first or second dice: it is the first die or second die. The probability is 1/6 * 1/2 = 1/12
Count the total number of ways it can turn out. Count the number of ways that are the condition you're looking for. The probability of the outcome you're looking for is is the second number divided by the first number.
Three out of twelve
The answer depends on whether the first number is replaced before picking the second. If not, the probability is 0.029
The first roll doesn't matter for probability, it just sets the number to be rolled by the other two. So: P(rolling the same number three times) = P(rolling a particular number)2 = (1/6)2 = 1/36
If you have one cube in the first solid than six cubes in the second solid and than fifteen cubes in the third solid, than you would get 215 cubes in the eighth solid.
3/5 or three fifths.