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Answer this a piece of poster has a perimeter of 130 cm what are the dimensions of the poster if its length is 35 cm longer than its width?
Suppose the width is W cm Then the length, L = W + 35 cm And the perimeter is 2W + 2L = 2W + 2(W+35) = 4W + 70 4W + 70 = 130 so that 4W = 60 or W = 15 and then L = W + 35 = 50 So the poster is 15 cm by 50 cm
A rectangle has a perimeter of 52 cm and a width of 12 cm What is the length?
P=2(w)+2(l) 52=2(12)+2(l) 52=24+2l 52-24=2l 28=2l 14=l The length is 14 cm.
How many ways can you draw a rectangle that has an area of 12cm?
You cannot draw a single rectangle which has an area of 12 cm because 12 cm is a measure of length, not area! There are an infinite number of rectangles with an area of 12 cm2. Let L be any length greater than or equal to sqrt(12) = 3.464 cm (approx) and let B = 12/L cm Then Area = L*B = 12 cm2 and each value of L gives a different rectangle.
What is the surface area (length X width X 6) cm X cm X 6 cm2?
It is (2*L*W + 12*L + 12*W) cm2.
What is the answer to the question the length of a rectangle is four times more than its width If the perimeter is 30 cm what are the length and width of the rectangle?
Length (l) is 4 x width (w). If 2 lengths and 2 widths equals perimeter, then 2l+2w=30 cm. Substituting 4w for l, you get 2(4w) + 2w = 30 cm. So in solving, 10w=30 cm; w=3. Then solve for l: 4w=l; l=12. Then check your answer: 2(l=12) + 2(w=3)= 30; 24=6=30 cm.
A rectangle has a width of 6 cm and a perimeter of 30 cm what is the length of the rectangle?
30=2(6)+2(l) 30=12+2(l) 18+2(l) length is 9 cm
Answer this a piece of poster has a perimeter of 130 cm what are the dimensions of the poster if its length is 35 cm longer than its width?
Suppose the width is W cm Then the length, L = W + 35 cm And the perimeter is 2W + 2L = 2W + 2(W+35) = 4W + 70 4W + 70 = 130 so that 4W = 60 or W = 15 and then L = W + 35 = 50 So the poster is 15 cm by 50 cm
A rectangle has a perimeter of 52 cm and a width of 12 cm What is the length?
P=2(w)+2(l) 52=2(12)+2(l) 52=24+2l 52-24=2l 28=2l 14=l The length is 14 cm.
How many ways can you draw a rectangle that has an area of 12cm?
You cannot draw a single rectangle which has an area of 12 cm because 12 cm is a measure of length, not area! There are an infinite number of rectangles with an area of 12 cm2. Let L be any length greater than or equal to sqrt(12) = 3.464 cm (approx) and let B = 12/L cm Then Area = L*B = 12 cm2 and each value of L gives a different rectangle.
What is the surface area (length X width X 6) cm X cm X 6 cm2?
It is (2*L*W + 12*L + 12*W) cm2.
What is the answer to the question the length of a rectangle is four times more than its width If the perimeter is 30 cm what are the length and width of the rectangle?
Length (l) is 4 x width (w). If 2 lengths and 2 widths equals perimeter, then 2l+2w=30 cm. Substituting 4w for l, you get 2(4w) + 2w = 30 cm. So in solving, 10w=30 cm; w=3. Then solve for l: 4w=l; l=12. Then check your answer: 2(l=12) + 2(w=3)= 30; 24=6=30 cm.
How do you Find the perimeter of a rectangle when the area is 168 square centimeters and the length of the side is 12 cm?
First find the width which is 168/12 = 14 cmPerimeter: 14+12+14+12 = 52 cm
150 of what length is 66 in?
If 150 / x = 66, then x = 2.2727 cmSuppose the length is L cm.Then 150*L cm = 66 cmSo L cm = 66 cm/150 = 66/150 cm = 0.44 cm = 4.4 mm.
What is the length of the side of a cube in cm that has a volume of 44.4 L?
The length of the side of a cube in cm that has a volume of 44.4 L is: 1.162 feet
The width of a rectangle is fixed at 14 cm What lengths will make the perimeter greater than 98 cm?
L + W = P/2 = 49 so Length must be greater than 35 cm
The perimeter of a rectangle is 90 cm. If the length is one and one-half times the width Find the length and the width?
Suppose the length is L cm. Then the width, W, is 2L/3 cm. Perimeter = 2(L+W) = 2(L+2L/3) = 10L/3 = 90 cm So L = 27 cm and W = 2L/3 = 18 cm.
If the length of a rectangle is 6 cm longer than twice the width and that the perimeter of the rectangle is 108 cm then what is the width and the length?
Suppose the width is w cm Then length is 2w + 6 cm So, the perimeter is 2l + 2w = 2*(2w + 6) + 2w = 4w + 12 + 2w = 6w + 12 Thus 6w + 12 = 108 so that 6w = 96 and then w = 16 cm And then, l = 2w + 6 = 32 + 6 = 38 cm
