L + W = P/2 = 49 so Length must be greater than 35 cm
P (perimeter of a rectangle) = 2*l+2*w 2*24+2*w > 100 2*w > 52 w > 26 Any width greater than 26cm will cause the perimeter to be greater than 100cm.
The perimeter of a rectangle is 2 x length + 2 x width. If the width is 16 then 78 = 2 x length + 2 x 16 2 x length = 78 - 32 = 46 length = 23. For the perimeter to be greater than 78 cm, the length must be greater than 23 cm
Conventionally, length > width. With that assumption, if L is the length and W the width (both in metres) then 3.75 < L < 7.5 and W = 7.5 - L If L = 3.75 then W = L and the rectangle becomes a square.
For a fixed area, the perimeter is minimum for a circle, but has no maximum. Fractal figures (such as Koch snowflake) may have a finite area within an infinite perimeter.
no If the shape of the object is not fixed, it would be possible to alter the shape of the perimeter, but not the length, i.e., the distance around the object being enclosed.
For a fixed perimeter, the area will always be the same, regardless of how you describe the rectangle.
The greatest area for a fixed perimeter will be when all the sides are equal or when the rectangle approaches the shape of a square.
Any length greater than 9 cm.
P (perimeter of a rectangle) = 2*l+2*w 2*24+2*w > 100 2*w > 52 w > 26 Any width greater than 26cm will cause the perimeter to be greater than 100cm.
nope because if u have a square with a side length of 4 then the perimeter is 16 and the area is 16 and say if u have a rectangle with side lengths of 2 and 6 then the perimeter is 16 but the area is 12 so the answer is no
You dont
The maximum area for a rectangle of fixed perimeter is that of the square that can be formed with the given perimeter. 136/4 = 34, so that the side of such a square will be 34 and its area 342 = 1156.
fixed perimeter is the perimeter being fixed
The perimeter of a rectangle is 2 x length + 2 x width. If the width is 16 then 78 = 2 x length + 2 x 16 2 x length = 78 - 32 = 46 length = 23. For the perimeter to be greater than 78 cm, the length must be greater than 23 cm
Anything greater than 24 cm. P = 2*L + 2*W, since the length is fixed at 24cm we have: 2*(24cm) +2*W > 96cm 2W > 96 - 48cm 2W > 48cm, or Width > 24cm. So any width greater than 24cm will make the perimeter >96cm. Obviously a width of 24cm wouldn't work since a polygon with all four sides equal would be a square and not a rectangle.
A perimeter that will not change.
Recall that the perimeter is: P=2*L+2*W If L=27 cm, find W such that P>86 cm P>86 cm 2*L+2*W>86 cm 54 cm+2*W>86 cm 2*W>32 cm W>16 cm So widths greater than 16 cm will make the perimeter greater than 16 cm.