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If the area of a triangle is 35 inches and the height is two inches less than the base would that make the base seven inches and the height five inches?
Wiki User
∙ 13y ago
nope. because the equasion of the area of a triange is A=1/2BH and if u plug it in it would be 1/2x7x5
1/2x35
17 1/2 does not = 35
Wiki User
∙ 13y ago
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What is the area of an equilateral triangle with sides 10 inches and height of 7 inches?
Area of the equilateral triangle: 0.5*10*10*sin(60 degrees) = 25 times square root of 3 which is about 43.301 square inches to 3 decimal places. If it is an equilateral triangle with 3 equal sides of 10 inches then its height would be about 8.66 inches and not 7 inches
Select all the triangles that would have an area of 18 square inches. Answer Choices A triangle with a base length of 9 in. and a height of 2 in. A triangle with a base length of 9 in. and a height of?
The first is clearly not a suitable triangle.
What is the area of a triangle with a base of 18 in and a height of 20 M?
The formula for the area of a triangle is 1/2bh, so one-half of the base times the height. With a base of 18 inches, one half of the base would be 9 inches. This, multiplied by the height of 20m converted to inches (787.4 inches) gives the problem 9 x 787.4 = 7086.6 in2, or 49.212 ft2
What is the formula for area for a triangular prism without the height?
It is impossible to find the area of a triangle with no height, if the triangle had no height it would not even be a triangle, just a angle.
What would the area of a triangle with a base of 20 in and a height of 5 in?
Area = 0.5*Base*Altitude = 0.5*20*5 = 50 square inches.
What is the area of an equilateral triangle with sides of ten inches and height of seven inches?
There is a problem with your question, namely that such a triangle does not exist. An equilateral triangle with sides of length 10 would have a height of 5 * (root 3), which is approx 8.66 (not 7 as the question states). An equilateral triangle of side length 10 inches would have an area of 25*(root 3), which is approx. 43.3 inches2.
What is the area of a triangle with a base of 8 inches and a height of 6 inches?
The formula for the area of a triangle is: (1/2)Base x Height So the triangle would have an area of (1/2)(8 inches)(6 inches) = 24 inches2
What is the area of a triangle with a base of 10 inches and a height of 3 inches?
The formula for finding the area of a triangle is half of the base x the height. For this triangle, it would be 1/2 of 10 X 3, or 15 square units.
How do you determine the area of triangles?
the formula for the area of a triangle is; a=1/2 base times height. so for example: a triangle may have a base length of 6 inches and a height of 3 inches. a=1/2 6(3) the answer would be: 9 inches.
What is the area of an equilateral triangle with side of 10 inches and height of 7 inches?
Area of the equilateral triangle: 0.5*10*10*sin(60 degrees) = 25 Times Square root of 3 which is about 43.301 square inches to 3 decimal places. If it is an equilateral triangle with 3 equal sides of 10 inches then its height would be about 8.66 inches and not 7 inches
What is the area of an equilateral triangle with sides 10 inches and height of 7 inches?
Area of the equilateral triangle: 0.5*10*10*sin(60 degrees) = 25 times square root of 3 which is about 43.301 square inches to 3 decimal places. If it is an equilateral triangle with 3 equal sides of 10 inches then its height would be about 8.66 inches and not 7 inches
Select all the triangles that would have an area of 18 square inches. Answer Choices A triangle with a base length of 9 in. and a height of 2 in. A triangle with a base length of 9 in. and a height of?
The first is clearly not a suitable triangle.
What is the area of a triangle with a base of 18 in and a height of 20 M?
The formula for the area of a triangle is 1/2bh, so one-half of the base times the height. With a base of 18 inches, one half of the base would be 9 inches. This, multiplied by the height of 20m converted to inches (787.4 inches) gives the problem 9 x 787.4 = 7086.6 in2, or 49.212 ft2
The height of a triangle is four times the length of the base find the base and height of the triangle if the base is 18 square inches?
18 square inches is probably the area of the triangle, not the length of the base. The length of the base would be measured in inches (a unit of length), not square inches (a unit of area). So area = 1 / 2 * base * height = 18 square inches (given) height = 4 * base (given) 1 / 2 * base * 4 * base = 18 square inches 2 * base * base = 18 square inches base * base = 9 square inches base = 3 inches height = 4 * base = 4 * 3 inches = 12 inches Checking our work: height is 4 times the base (12 = 4 * 3) area is 18 (1/2 * 12 * 3).
What is the formula for area for a triangular prism without the height?
It is impossible to find the area of a triangle with no height, if the triangle had no height it would not even be a triangle, just a angle.
What would the area of a triangle with a base of 20 in and a height of 5 in?
Area = 0.5*Base*Altitude = 0.5*20*5 = 50 square inches.
What type of triangle would have a base of 8 inches and two sides of 12 inches?
isoceles triangle
