Equilateral triangle means that all sides are equal in length. When it is asked for a height of equilateral triangle it refers to vertical distance from highest point of the triangle to the lowest(Right in the middle). So we got two known and one unknown which tells us that we can use Pythagorean Theorem C2=A2 + B2
A=4
B=?
C=8
Solve for B and you will get answer Square root of 48.
Its area is 46.8 (46.76533) square inches.
By definition, an equilateral triangle has all three sides of equal length! So it is impossible for it to have sides of length 10 inches and 7 inches!
Find the area of an equilateral triangle that has a perimeter of 21 inches. Round the answer to one decimal place.
9 inches
We know that the height of an equilateral triangle equals the product of one half of the side length measure with square root of 3.Since in our regular hexagon we form 6 equilateral triangles with sides length of 16 inches, the apothem length equals to 8√3 inches.
3 inches, an equilateral triangle has equal side lengths and angle measures
I'm showing it with absolute proof. Equilateral triangle both side are same in size & same angel.It's given with the sides of 10 inches & height 7 inches. I don't need to count the height(7),just use side(10).The formula is=Area of a equilateral triangle="root over of 3" /4 * "a square"Now I use this formula,where "a" is 10. So the answers come=43.3,which is 44.So the Correct answer is=44 inches.* * * * *Mostly correct, but:43.3 should be rounded to 43, not 44.The units for the area should be square inches, not inches.
Its area is 46.8 (46.76533) square inches.
Area of the equilateral triangle: 0.5*10*10*sin(60 degrees) = 25 Times Square root of 3 which is about 43.301 square inches to 3 decimal places. If it is an equilateral triangle with 3 equal sides of 10 inches then its height would be about 8.66 inches and not 7 inches
Area of the equilateral triangle: 0.5*10*10*sin(60 degrees) = 25 times square root of 3 which is about 43.301 square inches to 3 decimal places. If it is an equilateral triangle with 3 equal sides of 10 inches then its height would be about 8.66 inches and not 7 inches
A triangle with side 8 and height 10 cannot be equilateral if the side and height are measured in the same units (inches, cm, miles etc). And if they are not, there is not sufficient information to answer the question.A triangle with side 8 and height 10 cannot be equilateral if the side and height are measured in the same units (inches, cm, miles etc). And if they are not, there is not sufficient information to answer the question.A triangle with side 8 and height 10 cannot be equilateral if the side and height are measured in the same units (inches, cm, miles etc). And if they are not, there is not sufficient information to answer the question.A triangle with side 8 and height 10 cannot be equilateral if the side and height are measured in the same units (inches, cm, miles etc). And if they are not, there is not sufficient information to answer the question.
There is a problem with your question, namely that such a triangle does not exist. An equilateral triangle with sides of length 10 would have a height of 5 * (root 3), which is approx 8.66 (not 7 as the question states). An equilateral triangle of side length 10 inches would have an area of 25*(root 3), which is approx. 43.3 inches2.
A triangle with side a: 6, side b: 6, and side c: 6 inches has an area of 15.59 square inches.
Using Pythagoras' theorem it is impossible for an equilateral triangle with equal sides of 10 inches to have a height of 7 inches.
If all three sides are 9 inches in length, then it is an EQUILATERAL Triangle. All the angles are 60 degrees.
Height in inches = XV=15 Area of a triangle = base length times perpendicular height divided by 2 An equilateral triangle has three equal sides with three equal interior angles of 60o An equilateral triangle can be considered as being two right angled triangles joined together. So we can make use of trigonometry to find the base length: opposite/tangent = adjacent length of the right angled triangle 15/tangent 60o = 8.660254038 inches Base length of the equilateral triangle = 8.660254038*2 = 17.32050808 inches Area = 17.32050808*15/2 = 129.9038106 square inches Therefore the area of the equilateral triangle is 130 square inches which is correct to three significant figures. Answered by David Gambell, Merseyside, England.
18 inches and it is an equilateral triangle