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What is the 14th term in the arithmetic sequence in which the first is 100 and the common difference is -4? a14= a + 13d = 100 + 13(-4) = 48
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A single number, such as 11111, cannot define an arithmetic sequence. On the other hand, it can be the first element of any kind of sequence. On the other hand, if the question was about ``1, 1, 1, 1, 1'' then that is an arithmetic sequence as there is a common difference of 0 between each term.
What is the 14th term in the arithmetic sequence in which the first is 100 and the common difference is -4? a14= a + 13d = 100 + 13(-4) = 48
Arithmetic : (First term)(last term)(act of terms)/2 Geometric : (first term)(total terms)+common ratio to the power of (1+2+...+(total terms-1))
It is a + 8d where a is the first term and d is the common difference.
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The answer is two arithmetic sequences, both with a common difference of 3, alternating with one another, where the second series is greater than the first by the value of 2*A(0), ie twice the starting value.
From any term after the first, subtract the preceding term.
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For an Arithmetic Progression, Sum = 15[a + 7d].{a = first term and d = common difference} For a Geometric Progression, Sum = a[1-r^15]/(r-1).{r = common ratio }.
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First we define an arithmetic sequence as one where each successive term has a common difference and that difference is constant. An example might be 1, 4, 7, 10, 13, 16, ..where the difference is 3. 1+3=4, 4+3=7 etc. Here is a common example that is given as a problem but shows a real life example of arithmetic sequences. A theater has 60 seats in the first row, 68 seats in the second row, 76 seats in the third row, and so on in the same increasing pattern. If the theater has 20 rows of seats, how many seats are in the theater? The common difference is 8 and we want the the sum of the first 20 terms this gives us the sum of all the seats. We solve this by first finding the 20th term which is 212 and noting that the first term is 60. We add the first and the 20th terms in the sequence and multiply the sum by 20. Next we divide that product by 2. The sum we are looking for is 20(60+212)/2=2720 so there are 2720 seats in the theater! The general formula to find the sum of the first n terms in an arithmetic sequence is to multiply n by the sum of the first and nth terms in the sequence and divide that answer by 2. In symbols we write Sn=n(a1+ an)/2