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Q: If the length of each side of the square is increased by 10 percent by what percent does the area of the square increased?

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30%

area= side^2 let the symbol # denote error in measurement #area/area= 2(#length/length) #area/area*100= 2(#length/length)*100 percent error in area= 2*percent error in length=2% 2 per cent

The area is increased by a factor of 9.

I assume you mean the relationship between the length and the area. Indeed, it is non-linear. The increase in area is proportional to the square of the length of the side. For example, if the length of the side is increased by a factor of 10, the area is NOT increased by a factor of 10, but by a factor of 100.

The error in its area is then 2 percent....

It is increased by x sqrt(2).

0.01

1% off

1% off

The area is increased to 22 = 4 times what is was.The area is increased to 22 = 4 times what is was.The area is increased to 22 = 4 times what is was.The area is increased to 22 = 4 times what is was.

Each side is multiplied by 3, so the area is multiplied by 9, so the answer is 90.

The area of a square is the square of its side length.

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