Q: If the area of the square is increased by 69 percent how much the length of the side will increase?

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If the side of a square doubles, its area increases by a factor of 4 - an increase of 300%.If the side of a square doubles, its area increases by a factor of 4 - an increase of 300%.If the side of a square doubles, its area increases by a factor of 4 - an increase of 300%.If the side of a square doubles, its area increases by a factor of 4 - an increase of 300%.

2

The area of a square of length m is m2 Accordingly, for a square of side length 6 length units = 62 square units. = 36 square units

The length of a square is not determined by a formula, it is determined by measuring the square.

The length and width of a square are equal. Thus, find the square root of the area and the answer = length= width.

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10

By 44%. Here is how you calculate it: 20% increase is equivalent to an increase by a factor of 1.2 (100% + 20%, converted to decimal). Square that, and you get 1.44 (44% more than the original).

I assume you mean the relationship between the length and the area. Indeed, it is non-linear. The increase in area is proportional to the square of the length of the side. For example, if the length of the side is increased by a factor of 10, the area is NOT increased by a factor of 10, but by a factor of 100.

Time period is directly proportional to the square root of the length So as we increase the length four times then period would increase by ./4 times ie 2 times.

66

200%. Careful here! An 800% increase is equivalent to multiplying by 9 - NOT 8. So the sides need to be multiplied by sqrt(9) = 3. That is an increase of 200%

The percentage error in the area of the square will be twice the percentage error in the length of the square. This is because the error in the length affects both the length and width of the square, resulting in a compounded effect on the area. Therefore, if there is a 1 percent error in the length, the percentage error in the area would be 2 percent.

Each side will increase by the square root of 69 (approx. 8.3).

The area of a sphere is A=4*3.14 * r^2. Thus the area varies as the square of the radius. If the surface area is increased by a factor of 4, then the radius will have to increase by the square root of 4 which is 2.

increased by 60 percent as well. Momentum is directly proportional to kinetic energy when mass is constant according to the equation p = √(2mEk), where p is momentum, m is mass, and Ek is kinetic energy.

No. The change of the area is the square of the change of the length and width.If the length and width are 40% more, they got multiplied by 1.4 .So the area got multiplied by (1.4)2 = 1.96 . That's an increase of 96% .

The time period of a pendulum is directly proportional to the square root of its length. If the length of the pendulum is increased, the time period will also increase. Conversely, if the length is decreased, the time period will decrease.