0
What else can I help you with?
When an error of 1 percent is made in the length of a square the percentage error in the area of square will be?
The percentage error in the area of the square will be twice the percentage error in the length of the square. This is because the error in the length affects both the length and width of the square, resulting in a compounded effect on the area. Therefore, if there is a 1 percent error in the length, the percentage error in the area would be 2 percent.
Is the length of a side of a square and its area nonlinear?
I assume you mean the relationship between the length and the area. Indeed, it is non-linear. The increase in area is proportional to the square of the length of the side. For example, if the length of the side is increased by a factor of 10, the area is NOT increased by a factor of 10, but by a factor of 100.
When an error of 1 percent is made in the length of a square error is?
The error in its area is then 2 percent....
How does doubling the area of a square affect the side length?
It is increased by x sqrt(2).
If the surface area of a sphere is increased by a factor of 4 what is the change in the length of the radius of the sphere?
The area of a sphere is A=4*3.14 * r^2. Thus the area varies as the square of the radius. If the surface area is increased by a factor of 4, then the radius will have to increase by the square root of 4 which is 2.
If the area of the square is increased by 69 percent how much the length of the side will increase?
30%
When an error of 1 percent is made in the length of a square the percentage error in the area of square will be?
The percentage error in the area of the square will be twice the percentage error in the length of the square. This is because the error in the length affects both the length and width of the square, resulting in a compounded effect on the area. Therefore, if there is a 1 percent error in the length, the percentage error in the area would be 2 percent.
When an error of 1 percent is made in the length of a square the percentage of error in the area of a square will be?
area= side^2 let the symbol # denote error in measurement #area/area= 2(#length/length) #area/area*100= 2(#length/length)*100 percent error in area= 2*percent error in length=2% 2 per cent
Is the length of a side of a square and its area nonlinear?
I assume you mean the relationship between the length and the area. Indeed, it is non-linear. The increase in area is proportional to the square of the length of the side. For example, if the length of the side is increased by a factor of 10, the area is NOT increased by a factor of 10, but by a factor of 100.
If you triple the length of the sides of a square what happens to the area?
The area is increased by a factor of 9.
When an error of 1 percent is made in the length of a square error is?
The error in its area is then 2 percent....
How does doubling the area of a square affect the side length?
It is increased by x sqrt(2).
When an error of 1 percent is made in the length of square the percentage error in the area of a square will be?
1% off
What happens to the area of a square when the side length is doubled?
The area is increased to 22 = 4 times what is was.The area is increased to 22 = 4 times what is was.The area is increased to 22 = 4 times what is was.The area is increased to 22 = 4 times what is was.
A square has an area of 10 If the side length is increased by a factor of 3 what is the new area of the square?
Each side is multiplied by 3, so the area is multiplied by 9, so the answer is 90.
What is the relationship between the area of a square and the length of a side?
The area of a square is the square of its side length.
If the surface area of a sphere is increased by a factor of 4 what is the change in the length of the radius of the sphere?
The area of a sphere is A=4*3.14 * r^2. Thus the area varies as the square of the radius. If the surface area is increased by a factor of 4, then the radius will have to increase by the square root of 4 which is 2.
