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Q: If two numbers are complementary what is their probability?

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The probability is 0.

The probability of getting two prime numbers when two numbers are selected at random and without replacement, from 1 to 10 is 2/15.

If an event is absolutely certain to happen is then we say the probability of it happening is 1.Complementary events are such that one of the events musthappen. Therefore the probability of one of a set of complementary events occurring is 1.For instance : The probability that a fair coin when tossed will come down showing heads is 1/2, and that it will show tails is also 1/2.The two events are complementary so the probability that the coin toss will result in either a heads or a tails is 1.Similarly, the probability that a die when rolled will show a number 1, 2, 3, 4, 5 or 6 is 1 as all six events are complementary.

If the probability of an event is p, then the complementary probability is 1-p.

Not necessarily. The probability of a complementary event with probability p is 1-p. Two mutually exclusive events, however, don't necessarily add up to a probability of 1. For example, the probability of drawing a King from a standard deck of cards is 1 in 13, which the complementary probability of not drawing a King is 12 in 13. The probability, however, of drawing a Heart is 1 in 4, while the probability of drawing a Club is also 1 in 4. That leaves Diamonds and Spades, which account for the remaining probability of 2 in 4.

In two successive rolls, it is 1/6 otherwise it is a near certainty.

Two events A and B or complementary if A and B are "opposites". If A happens it means that B cannot happen and if B happens it means that A cannot happen.

These events are complementary. Let P(A) = probability event will occur. Then the probability it will not occur is: 1 - P(A).

The probability is 5/6.

Suppose there is an event A and the probability of A happening is Pr(A). Then the complementary event is that A does not happen or that "not-A" happens: this is often denoted by A'.Then Pr(A') = 1 - Pr(A).Suppose there is an event A and the probability of A happening is Pr(A). Then the complementary event is that A does not happen or that "not-A" happens: this is often denoted by A'.Then Pr(A') = 1 - Pr(A).Suppose there is an event A and the probability of A happening is Pr(A). Then the complementary event is that A does not happen or that "not-A" happens: this is often denoted by A'.Then Pr(A') = 1 - Pr(A).Suppose there is an event A and the probability of A happening is Pr(A). Then the complementary event is that A does not happen or that "not-A" happens: this is often denoted by A'.Then Pr(A') = 1 - Pr(A).

Complementary events are events that are the complete opposite. The compliment of event A is everything that is not event A. For example, the complementary event of flipping heads on a coin would be flipping tails. The complementary event of rolling a 1 or a 2 on a six-sided die would be rolling a 3, 4, 5, or 6. (The probability of A compliment is equal to 1 minus the probability of A.)

1/9

The probability of rolling two prime numbers on a standard pair of dice is 1 in 4, or 0.25. Take the probability of rolling a prime on one die, 3 in 6, or 1 in 2, or 0.5, and square it.

which two of these three events are complementary? a. The probablity that a student makes more than 13 mistakes is .32 B. The probability that a student makes 3 or more mistakes is .56 C. The probability that a student makes at most 13 mistakes is .68

It is 7/36 = 0.1944... recurring.

It's1/12

About 98 percent.

The probability of rolling two even numbers on two standard dice is 0.52, or 0.25.

2 numbers. few probabilities. Lets see. Number 1 probability: if your given numbers are this for example, 2 and 7. What is the probability of picking out 7? the Numerator is how many of that number is in the group. They are asking for 7? so how many 7's are in the group? 1. Then the denominator is how many numbers are in the group. There are 2 numbers in the group. so the probability of picking out a 7 would be 1/2. get it? if there were two 7's, then the probability would be 2/2 or 1. I hope I helped.

The probability that a spinner with N sides stops on 2 particular numbers in two spins in 1 in N2. It does not matter what the two numbers are, since the two spins are sequentially unrelated.

The probability is approx 0.09. This assumes that J and K are not prime numbers.

The answer depends on how many dice you roll and how often. If you roll four dice once, the probability of getting a double AND two odd numbers is 264/1296 = 11/54

"Complementarity" may be "the property of being complementary" or something like that. In geometry, two angles are said to be complementary if their sum is equal to 90 degrees. For example, 30o and 60o are complementary because 30o + 60o = 90o. There are also a number of other applications of the term "complementary" in mathematics. One more might be its use in probability and statistics. If the sum of two probabilities is one, they are said to be complementary. Here's a killer example: On a given coin toss, the probability of a head coming up is complimentary to the probability of a tail coming up. The actual formula is P(A) + P(B) = 1 In a quickie review of probability as it is used here, if something cannot possibly happen, the probability of it happening is zero. If something absolutely will occur without any possibility of anything else happening, the probability of that event happening is one. So probabilities range between zero and one (inclusive). The probability of a head coming up in a coin toss is one 1 in 2, or 50%, or 0.5 (speaking in mathematical terms of probability). The probability of a tail is the same (0.5). Let's just do a quick math thingie with that and get it to lock in: Probability of a head = Ph = 0.5 Probability of a tail = Pt = 0.5 Ph + Pt = 0.5 + 0.5 = 1.0 Ph and Pt are said to be complementary, since Ph + Pt = 1.0

Prob(Sum = 5) = 1/9

No only two angles can be complementary