There is a 40% chance that it will be an odd number.
Explanation:
The first five prime numbers are 2, 3, 5, 7, and 11. If one of the two numbers chosen is 2, the sum of the two numbers will be odd.
2 + 3 = 5
2 + 5 = 7
2 + 7 = 9
2 + 11= 13
But, if both numbers chosen are odd, the sum will be an even number.
3 + 5 = 8
3 + 7 = 10
3 + 11 = 14
5 + 7 = 12
5 + 11 = 16
7 + 11 = 18
So, there are four possible combinations out of 10 that result in a sum that is odd.
Another way to do this, without listing the possible combinations, is to determine the chance of randomly selecting the 2. Two numbers are being chosen from five, so there is a 2/5 = 40% chance of selecting a 2, which means the sum will be odd.
The probability, in a single random selection, is 1/20 or 0.05
3 out of 4
90%
From 75 to 100 (inclusive), there are 26 numbers, and 13 of them are odd.The probability of picking an odd number is 13/26 = 50%.
If the winning numbers are picked at random, the probability is 1 in 169911.
The probability of getting two prime numbers when two numbers are selected at random and without replacement, from 1 to 10 is 2/15.
The probability of selecting a 17 (or any number for that matter) is 1/20 or .05 or 5%.
The probability is 10 percent.
The probability, in a single random selection, is 1/20 or 0.05
The probability is the number of girls divided by the number of students, so 12/22, or 6/11
3 out of 4
90%
1/365 = 0.00274
It depends on what the random variable is, what its domain is, what its probability distribution function is. The probability that a randomly selected random variable has a value between 40 and 60 is probably quite close to zero.
From 75 to 100 (inclusive), there are 26 numbers, and 13 of them are odd.The probability of picking an odd number is 13/26 = 50%.
probability = 2/7 to be exact, 28/97 (about 28.87%)
If the winning numbers are picked at random, the probability is 1 in 169911.