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If two numbers are selected at random from the first five prime numbers What is the probability that their sum is an odd number?
Wiki User
∙ 14y ago
There is a 40% chance that it will be an odd number.
Explanation:
The first five prime numbers are 2, 3, 5, 7, and 11. If one of the two numbers chosen is 2, the sum of the two numbers will be odd.
2 + 3 = 5
2 + 5 = 7
2 + 7 = 9
2 + 11= 13
But, if both numbers chosen are odd, the sum will be an even number.
3 + 5 = 8
3 + 7 = 10
3 + 11 = 14
5 + 7 = 12
5 + 11 = 16
7 + 11 = 18
So, there are four possible combinations out of 10 that result in a sum that is odd.
Another way to do this, without listing the possible combinations, is to determine the chance of randomly selecting the 2. Two numbers are being chosen from five, so there is a 2/5 = 40% chance of selecting a 2, which means the sum will be odd.
Wiki User
∙ 14y ago
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