There is a 40% chance that it will be an odd number.
Explanation:
The first five prime numbers are 2, 3, 5, 7, and 11. If one of the two numbers chosen is 2, the sum of the two numbers will be odd.
2 + 3 = 5
2 + 5 = 7
2 + 7 = 9
2 + 11= 13
But, if both numbers chosen are odd, the sum will be an even number.
3 + 5 = 8
3 + 7 = 10
3 + 11 = 14
5 + 7 = 12
5 + 11 = 16
7 + 11 = 18
So, there are four possible combinations out of 10 that result in a sum that is odd.
Another way to do this, without listing the possible combinations, is to determine the chance of randomly selecting the 2. Two numbers are being chosen from five, so there is a 2/5 = 40% chance of selecting a 2, which means the sum will be odd.
The probability, in a single random selection, is 1/20 or 0.05
To find the probability of selecting a number from 20 to 30 that is divisible by 3, we first identify the numbers in that range: 21, 24, 27, and 30. There are four suitable candidates, so the probability of selecting one of them is 4 out of 11 (the total numbers from 20 to 30, inclusive). After replacing the selected number, we check which of these are divisible by 12. Among the numbers listed, only 24 is divisible by 12. Therefore, the probability of selecting a number divisible by 3 and then finding it divisible by 12 is 1 out of 11, which simplifies to approximately 0.0909 or 9.09%.
3 out of 4
From 75 to 100 (inclusive), there are 26 numbers, and 13 of them are odd.The probability of picking an odd number is 13/26 = 50%.
probability = 2/7 to be exact, 28/97 (about 28.87%)
The probability of getting two prime numbers when two numbers are selected at random and without replacement, from 1 to 10 is 2/15.
The probability of selecting a 17 (or any number for that matter) is 1/20 or .05 or 5%.
The probability is 10 percent.
The probability, in a single random selection, is 1/20 or 0.05
The probability is the number of girls divided by the number of students, so 12/22, or 6/11
To find the probability of selecting a number from 20 to 30 that is divisible by 3, we first identify the numbers in that range: 21, 24, 27, and 30. There are four suitable candidates, so the probability of selecting one of them is 4 out of 11 (the total numbers from 20 to 30, inclusive). After replacing the selected number, we check which of these are divisible by 12. Among the numbers listed, only 24 is divisible by 12. Therefore, the probability of selecting a number divisible by 3 and then finding it divisible by 12 is 1 out of 11, which simplifies to approximately 0.0909 or 9.09%.
3 out of 4
1/365 = 0.00274
From 75 to 100 (inclusive), there are 26 numbers, and 13 of them are odd.The probability of picking an odd number is 13/26 = 50%.
It depends on what the random variable is, what its domain is, what its probability distribution function is. The probability that a randomly selected random variable has a value between 40 and 60 is probably quite close to zero.
probability = 2/7 to be exact, 28/97 (about 28.87%)
If the winning numbers are picked at random, the probability is 1 in 169911.