The probability of selecting a 17 (or any number for that matter) is 1/20 or .05 or 5%.
2 numbers. few probabilities. Lets see. Number 1 probability: if your given numbers are this for example, 2 and 7. What is the probability of picking out 7? the Numerator is how many of that number is in the group. They are asking for 7? so how many 7's are in the group? 1. Then the denominator is how many numbers are in the group. There are 2 numbers in the group. so the probability of picking out a 7 would be 1/2. get it? if there were two 7's, then the probability would be 2/2 or 1. I hope I helped.
yes.
There are 90 two-digit numbers from 10 to 99. Of those, 6 are perfect squares (16, 25, 36, 49, 64, and 81) and 2 are perfect cubes (27 and 64). Each perfect square or root has a probability of 1 in 90 in being drawn.
it depends on how many numbers are on the number cube. if it only goes to 6, then the probability is 1/6. if it goes to 8 then the probability is 2/8. and so on and so on...
An expression.
The probability of getting two prime numbers when two numbers are selected at random and without replacement, from 1 to 10 is 2/15.
The answer depends on how many numbers are selected.The answer depends on how many numbers are selected.The answer depends on how many numbers are selected.The answer depends on how many numbers are selected.
The event space comprises the numbers 10 to 99, 90 such numbers. The favourable events are 15, 21, 27, ... , 99. There are 15 such numbers. So the probability is 15/90 = 1/6
It is called probability. All numbers have an equal opportunity of being selected and if they run the lottery say for 100 billion times they all will probably be selected.
10
53 - 1 or 1 chance in 54 or 0.0185 or 1.85%
Any normal die contains three numbers that are less than 4 so the answer must be 1.
To find the probability of selecting a number from 20 to 30 that is divisible by 3, we first identify the numbers in that range: 21, 24, 27, and 30. There are four suitable candidates, so the probability of selecting one of them is 4 out of 11 (the total numbers from 20 to 30, inclusive). After replacing the selected number, we check which of these are divisible by 12. Among the numbers listed, only 24 is divisible by 12. Therefore, the probability of selecting a number divisible by 3 and then finding it divisible by 12 is 1 out of 11, which simplifies to approximately 0.0909 or 9.09%.
There are 10 numbers {1, 2, ..., 10} The solution set contains {4, 5, ...,10} - 7 numbers in total → probability = number of successful tries/total number of tries = 7/10 = 0.7
50%, or 1 out of 2. There are 12 numbers, 6 even and 6 odd, so they have equal chance of being odd or even if one is selected
What is the probability of rolling an even with one roll of a numbers cube.
no they are not