answersLogoWhite

0


Best Answer

Each digit can appear in each of the 4 positions.

There are 9 digits, therefore there are 9⁴ = 6561 such combinations.

User Avatar

Wiki User

โˆ™ 2017-06-01 07:22:09
This answer is:
๐Ÿ™
0
๐Ÿคจ
0
๐Ÿ˜ฎ
0
User Avatar
User Avatar

Jack Kolars

Lvl 1
โˆ™ 2021-05-09 13:15:56
Can you list the 6561 combinations?

Add your answer:

Earn +20 pts
Q: If using numbers 1 through 9 how many different 4 digit combinations can be made with no restrictions on order or repeats?
Write your answer...
Submit
Related questions

If using numbers 0 through 9 how many different 4 digit combinations can be made with no restrictions on order or repeats?

In other words, how many 4 digit combination locks are there using the digits 0-9 on each wheel. There are 10×10×10×10 = 10⁴ = 10,000 such combinations.


How many different ways can I place 4 numbers?

Without repeats, 24. With repeats, 256.


How many combinations can be made from 1234567890?

If repeats are allowed than an infinite number of combinations is possible.


How is a rational number that repeats different from a irratrional number that repeats?

Irrational numbers can not be repeating decimals. Any number that is a repeating decimal is rational.


How many 3 digit combinations can be formed using 0 5 7 8?

Assuming you are using combinations in the colloquial way (which is the mathematical "permutations" where order of selection does matter) to create a 3 digit number that does not start with 0, ie creating a number that is between 100 and 999 inclusive then: If repeats are not allowed there are 3 × 3 × 2 = 18 possible numbers If repeats are allowed, then there are 3 × 4 × 4 = 48 possible numbers. If you are using combinations in the mathematical sense where order of selection does not matter and are creating groups of 3 digits, then: If repeats are not allowed there are 4 possible groups If repeats are allowed there are 20 possible groups.


How do you generate a list of five digit combinations of only the numbers 1 2 3 4 and 5 with out repeats?

you could make a probability tree if you could be bothered


How many different 2 digit numbers can be formed from the digits 2 6 7 and 8?

Without repeats there are 4 × 3 = 12 possible 2 digit numbers. With repeats there are 4 × 4 = 16 possible 2 digit numbers.


How many 6 number combinations can you make with numbers 1-50. No 1 number repeats?

The number of combinations is 50C6 = 50*49*48*47*46*45/(6*5*4*3*2*1) = 15,890,700


How many 8 number combinations are their using numbers 0 -9?

there are 10 numbers that you can choose from 0-9 you are choosing 8 at a time, meaning no repeats so the answer is "10 choose 8" or 10!/(8!*(8-2)!)


How many 3 digit even numbers can be formed by using numbers 01234?

Assuming leading zeros are not permitted, then: If repeats are not allowed there are 30 possible numbers. If repeats are allowed there are 60 possible numbers.


How many 6 number combinations can made from 50 numbers 1-50?

We are not told anything about repeats so I will assume you can repeat a digit. For example, you can have 111111 The first digits has 50 choices so does the second and the third..etc so we have 50^6 combinations.


How many number combinations can be made with 10 digits?

Allowing repeats, but not leading 0s, the answer is 9,000,000,000


How many odd 3- digit positive integers can be written using the digits 1 2 4 7 and 8?

If repeats are permitted: 2 x 5 x 5 = 50 different odd numbers If repeats are not permitted: 2 x 4 x 3 = 24 different odd numbers


How many possible alphanumeric 2 character combinations?

If repeats are permitted: (36 x 36) = 1,296If repeats are not permitted: (36 x 35) = 1,260If repeats are not permitted and the sequence doesn't matter: (36 x 35) / 2 = 630


How many social security numbers can there be if the first digit cannot be a zero and repeats are allowed?

Well if repeats are allowed, then unlimited. If you can repeat the numbers then the list would go on forever.


What is a fraction or a decimal that repeats?

They form a proper subset of rational numbers.


What are all 5 digit combinations with 1-9?

from 1-9 have 9 numbers so that we have 9*9*9*9*9=59049 Consider the case of 5-digit number combinations, where each is some digit from 1 through 9. There are 9 different digits you can pick for the first number. Assuming you can have repeats, there are 9 you can pick for the second, 9 you can pick for the third, and 9 you can pick for the fourth and 9 you can pick for the fifth.


How many two digit numbers can be made using the digits 1234?

With repeats: 4×4 = 16; Without repeats: 4×3 = 12.


How many number combinations can you make out of the numbers 1-6?

7


How many 5 numbers combinations can you make from the numbers 1 to 49 and you can use multiple combinations but still use each number only once?

If the 1, 2, 3, 4 and 5 each appear in the numbers (no repeats, no eliminations-- so numbers like 11133 are not valid) then there are 120 combinations. If you can use any of the 5 any number of times up to a max of 5 times, (any possible way of making a 5 digit number using only 1, 2, 3, 4 and 5, so that 33455 for example is valid) then the number of combinations is 3125. The 3125 combinations include the 120 combinations above. This is a permutation of 5 objects, that can be thought of as an arrangement or a rearrangement of the five numbers. The number of permutations of this 5 numbers is equal to 5!. 5! = 5 x 4 x 3 x 2 x 1 = 120 ways. Or you can use the graphing calculator to compute 5!, such as: Press 5, MATH, with the right arrow go to PRB, press 4 (for !), ENTER.


What is a number that never repeats or terminates?

Numbers that never repeat or terminate are called irrational numbers. Pi is one example.


What are the rationnal numbers?

Any number that terminates and repeats. 0.44444 is a rational number, fractions are rational and whole numbers are too.


How do you repeat decimals?

You write a bar above one or more numbers (you have to write it after one or more numbers or the decimal).It repeats.


How many 4 number combinations are there in 33 numbers?

Assuming there is no repetition, you want the number of groups of 4 numbers, and the order doesn't matter: this is calculated as 33 over 4; which is the same as (33 x 32 x 31 x 30) / (1 x 2 x 3 x 4)


How many 4-digit numbers can be formed using the numbers 5 6 7 and 8?

Without repeats, 4*3*2*1 = 24 If repeats are allowed, then 4*4*4*4 = 256