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Dwight Jacobi
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∙ 7y agoIf y varies directly with x squared and if y = -9 when x = -1 then k = -9
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What formula would you use to find the distance from one point to another?
The Distance Formula! D = square root of (y2-y1) quantity squared + (x2-x1) quantity squared
Does distance have a formula?
Distance = the square root of (x2-x1)2 + (y2-y1)2Added:Distance Formula: Given the two points (x1, y1) and (x2, y2), the distance between these points is given by the formula:square root of x2-x1 squared +y2-y1 squared
How do you find linear equations with just coordinates?
if we take the (x1,y1),(x2,y2) as coordinates the formula was (x-x1)/(x2-x1)=(y-y1)/(y2-y1)
How do you use a variance-covariance matrix to obtain least squares estimates?
Suppose that you have simple two variable model: Y=b0+b1X1+e The least squares estimator for the slope coefficient, b1 can be obtained with b1=cov(X1,Y)/var(X1) the intercept term can be calculated from the means of X1 and Y b0=mean(Y)-b1*mean(X1) In a larger model, Y=b0+b1X1+b2X2+e the estimator for b1 can be found with b1=(cov(X1,Y)var(X2)-cov(X2,Y)cov(X1,X2))/(var(X1)var(X2)-cov(X1,X2)2) to find b2, simply swap the X1 and X2 terms in the above to get b2=(cov(X2,Y)var(X1)-cov(X1,Y)cov(X1,X2))/(var(X1)var(X2)-cov(X1,X2)2) Find the intercept with b0=mean(Y)-b1*mean(X1)-b2*mean(X2) Beyond two regressors, it just gets ugly.
What is the equation to find the midpoint?
The mid-point of the line segment of (x1, y1) and (x2, y2) is (x1+X2)/2 and (y1+y2)/2
How do you find the distance between two coordinates in geometry?
square root(x2-x1)squared+(y2-y1)squared
X plus one over x squared plus two?
it equals x1 it equals x1
What formula would you use to find the distance from one point to another?
The Distance Formula! D = square root of (y2-y1) quantity squared + (x2-x1) quantity squared
Does distance have a formula?
Distance = the square root of (x2-x1)2 + (y2-y1)2Added:Distance Formula: Given the two points (x1, y1) and (x2, y2), the distance between these points is given by the formula:square root of x2-x1 squared +y2-y1 squared
What is the squared deviation from the mean?
A set of numbers will have a mean, which is defined as the sum of all the values divided by the number of values. Suppose this mean is m. For each of the values, the squared deviation is the square of the difference between that value and m. Algebraicly, if you have a set {x1, x2, x3, ... , xn}, whose mean is m, then the squared deviation from the mean for x1 is (x1 - m)2.
Where can someone purchase a Dell Latitude x1?
One can purchase a Dell Latitude X1 directly from the official Dell website where one can also define the specifications according to one's needs. One can also find a pre-built Dell Latitude X1 at websites such as Amazon and eBay.
What is x squared plus five x minus fourteen?
The answer is: X1 = 2 X2 = -7
What is the distance between points 8 2 and 3 8?
Square root of 61. Distance formula is: square root of ((x1-x2)squared + (y2-y1)squared))
Find number of integer solution of X1 x2 x324?
find number of integer solution of X1+x2+x3=24
What is the difference between Regula-falsi method and secant method?
Regula-Falsi Method evaluates using assumed variables like "a", "b", f(a), f(b) Secant Method Directly works with x1, x2, f(x1), f(x2) Difference is in the Assignment pattern only, otherwise both are used to find root of Non-Linear equations using the same procedure which is: x1= [a * f(b) - b * f(a)]/[f(b)-f(a)] x1= [x0 * f(x1) - x1 * f(x0)]/[f(x1)-f(x0)] Thank You :-)
How do you find linear equations with just coordinates?
if we take the (x1,y1),(x2,y2) as coordinates the formula was (x-x1)/(x2-x1)=(y-y1)/(y2-y1)
How do you find the The initial range of Bisection method?
If this is in the context of finding a root of an equation, the answer is to make some guesses. Find value x1 and x2 such that f(x1) and f(x2) have opposite signs. Then, provided that f is a continuous function over (x1, x2), the bisection method will find its root.
