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If yoiu mean pt A = ( 8,2) & B = (3,8)
We apply Pythagoras.
Distance 'd^(2)' = (x(A) - x(B))^2 + (y)A) - y(B))^(2)
Substituting
d^)2 = (8 - 3)^(2) + ( 2 - 8)^(2)
d^(2) = 5^(2) + -6^(2)
d^(2) = 25 + 36
d^(2) = 61
d = sqrt(61)
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BeauSquare root of 61.
Distance formula is: square root of ((x1-x2)squared + (y2-y1)squared))
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