Both of the constants must be negative.
x2-8x+12 = (x-2)(x-6) That 2 numbers added together equals -8 and when multiplied equals 12
By the way it is not an equation because it is a quadratic expression.
Two is a prime factor of that equation.
You don't! There are no common factors.
( x - y )2There isn't enough information to answer this question because they have two squared variables and you do not know what is being squared. You would first need to either know the value of one of the variables and an equation of the value of both of the variables before you would be able to factor.
NO!!! x^2 + 1 = x^2 + 1^2 . This does NOT factor!!!!! Remember , two squared terms with a positive between them, does NOT factor. However, two squared terms with a negative between them does factor. e.g. x^2 - 1^2 = ( x + 1)(x - 1) Note the change of signs inside the brackets. So taking the Pythagorean equation ; a^2 + b^2 = c^2,, this does NOT factor. However, algebraically rearranging we have a^2 = c^2 - b^2 does factor to a^2 = (c - b)(c + b)
20x2 - 3x + 10 does not have any real factors.
one will contain a minus sign and the other will contain a plus sign
-9(x + 8)
This is a quadratic equation, and so you it falls under the rule: ax squared + bx + c. This means you need to times the 2x squared by 15, which is 30. Then you need to find the factors of thirty, i.e. 3 and 10, 15 and 2, 5 and 6. You need to find the pair of factors that add to make -13x, which would be -3 and -10. you then need to put these into the equation - it would become 2x squared -10x (as one equation) and -3x +15 would be another equation. we can see that 2x squared and -10x have 2x in common, and so the answer for that would be 2x (x - 5). the second equation would be -3 (x - 5). the two equations have x - 5 in common, and that would make up the first set of brackets. you then add the rest (2x - 3) and your answer would be (x - 5) (2x - 3).
There are no rational factors.
The positive number tells you that the brackets will be both pluses or both minuses.
Two is a prime factor of that equation.
There are no rational factors.
You don't! There are no common factors.
(-X + 3 ) Like that? Multiply by -1 (X - 3 )
There are no prime factors in that equation.
This is a basic quadratic equation. The question must be regarded as, How do you factor x² - 36 = 0 ? This equation can be written as x² - 6² = 0, which factors as (x + 6)(x - 6) = 0 This leads to the solutions (or roots) x = -6 and x = 6, often written as x = ±6
That means that both of your brackets will have minus signs.