I hope you mean x3+2x2-9x+18. Treat the equation like two equations: x3+2x2 and 9x+18. Factor out x2 from the first equation, so x2(x+2). Factor out 9 from the second equation, so 9(x+2). Now, the whole equation. x2(x+2)-9(x+2). Factor out (x+2), so (x+2)(x2-9). (x2-9) factors into (x+3)(x-3). So, (x+2)(x+3)(x-3) is the complete factorization. Hope this helps.
7
5x2 + 9x + 13 has no real factors.
That doesn't factor neatly. Applying the quadratic equation, we find two real solutions: (31 plus or minus the square root of 401) divided by 20x = 2.5512492197250394x = 0.5487507802749606
9x(x2+3x-10) * * * * * 9x3 + 27x2 - 90x = 9x(x2 + 3x - 10) = 9x(x + 5)(x - 2).
x2-9x can be factored by taking x out of each term x(x-9)
It is a quadratic equation in x.
You don't need to factor that; you can add them together, since they have the same variable.However, assuming you might mean 81x squared + 9x, you can take out the common factor, which is 9x.
Type your answer here... 81
(3x-4)(3x+4)
9x2 + 8x - 1 = (9x - 1)(x + 1)
(9x + 8)(9x - 8)
9x squared-15x squared = -6
It is a difference of squares. 9x^2-49=(3x+7)(3x-7)
x2 - 9x + 8 = (x-1)(x-8)
(3x + 8)(3x - 8)
x = ±2